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3 years ago

In the heat equation, what does c represent

Physics

2 answers:

Bingel [31]3 years ago

5 0

Heat equation, Q = m.c.Δt
Here, c represents " the specific heat of the substance "

Hope this helps!

sveticcg [70]3 years ago

5 0

Answer : 'c' represent the 'Specific heat of substance'.

Explanation :

Specific heat : It is defined as the amount of heat required to raise the temperature of 1 kilogram of substance by one degree Celsius. The S.I unit of specific heat is, Joule per kelvin (J/K).

Formula for specific heat,

$c=\frac{Q}{m\Delta T}$

where,

c = specific heat capacity of substance

Q = heat required

m = mass of substance

$\Delta T$ = change in temperature

Hence, 'c' represent the 'Specific heat of substance'.

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On the surface of the earth the weight of an object is 200 lb. Determine the height of the

siniylev [52]

Answer:

The height of the object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

We need to calculate the value of $Gmm_{e}$

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$200=\dfrac{Gmm_{e}}{(3958.756)^2}$

$200\times(3958.756)^2=Gmm_{e}$

$Gmm_{e}=3.134\times10^{9}$

We need to calculate the height of the object

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$125=\dfrac{200\times(3958.756)^2}{r^2}$

$r^2=\dfrac{200\times(3958.756)^2}{125}$

$r^2=25074798.5$

$r=\sqrt{25074798.5}$

$r=5007.4\ miles$

Hence. The height of the object is 5007.4 miles.

7 0

3 years ago

An Airbus A380 airliner can takeoff when its speed reaches 80 m/s. Suppose its engines together can produce an acceleration of 3

Tomtit [17]

Answer:

(a). The time is 26.67 sec.

(b). The distance traveled during this period is 1066.9 m.

Explanation:

Given that,

Speed = 80 m/s

Acceleration = 3 m/s

Initial velocity = 0

(a). We need to calculate the time

Using equation of motion

$v = u+at$

$t = \dfrac{v-u}{a}$

Put the value into the formula

$t = \dfrac{80-0}{3}$

$t =26.67\ sec$

The time is 26.67 sec.

(b). We need to calculate the distance traveled during this period

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

$s = 0+\dfrac{1}{2}\times3\times(26.67)^2$

$s =1066.9\ m$

The distance traveled during this period is 1066.9 m.

Hence, This is the required solution.

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3 years ago

Plz help will mark the brainliest

fenix001 [56]

Answer:

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3 0

3 years ago

Read 2 more answers

Suppose a star the size of our Sun, but of mass 9.0 times as great, were rotating at a speed of 1.0 revolution every 17 days. If

Tanya [424]

Use the conservation of angular momentum; angular momentum at the beginning = angular momentum at the end
Conservation of angular momentum:
I1 w1 = I2 w2
Where I is the moment of inertia. For a sphere, I=2/5 m R^2. Substituting into the equation above we get
w2 = I1 w1 / I2 = w1 m1 R1^2 / (m2 R2^2)
w2 = w1 4 * (R1/R2)^2
= 4*(1)*(7E5/7.5)^2
= 3.48E10 revs/(17days)
= 2.04705882 x 10^9 revs/sec

4 0

3 years ago

Molly is pulling a cart down the hallway. She stops at each classroom and collects a stack of books from each teacher. After sto

scZoUnD [109]

Answer:

His third law states that for every action or force in nature there is an equal and opposite reaction.

Explanation:

The heavier the books get, the harder it is for Molly to exert enough force to move the cart.

<em>I hope this helps!!!!!! Please mark me brainliest!!</em>

7 0

3 years ago