Answer:
yes that is the correct answer
In the standard form of the equation
![\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%5C%20f%28t%29%3DAcos%5Bb%28t%5Cpm%20c%29%5D%2Bk%5C%5C%20%5C%5C%20)
The middle line =k
For our given problem
f(t) = 40cos (80t + 20)
On comparison we get k=0
Hence middle line=0
Answer:
false because each go up by two and I didnt even look it up
Remark
All you need is 2 points to get the line of the equation. One is itself (B and B') is the same in both triangles. Now we need to find one more point. Since this is a reflection, the midpoint between C and C' is the second point. That choice of C and C' is completely arbitrary.
Step One
y intercept of the line. That point is B which is (0,1)
Step Two
Find the midpoint between C and C'
C is (-4,-2) and C' is ( 0 , - 4) The midpoint is
C" = (x2 + x1)/2 , (y2 + y1)/2
C" = (-4 + 0 )/2 , (-2 + - 4) / 2
C" = (-4)/2 , - 6/2
C" = (-2, - 3) C" is the midpoint between C and C'
Step 3
Find the equation of the line.
y = ax + b We are trying to find A
y = ax + 1
-3 = a(-2) + 1
-3 - 1 = a(-2)
- 4 = a(-2) Divide by -2
-4/-2 = a
a = 2
The slope of the line is 2
Answer
y = 2x + 1
It is the second option or b