All categories

3 years ago

four times the sum of a number and 15 is at least 120. Let x represent the number. Find all possible values for x.

1 answer:

7 0

The solution to the problem about the possible values of x in the inequality is as follows:

4(x+15) >= 120
x+15 >= 30
<span>x >= 15

Therefore, there are </span><span>x >= 15 possibilities in the inequality.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>

You might be interested in

garrett wants to build an addition to his living room. the room currently has a length of 13 feet and width of 10 feet. if he cr

marta [7]

Answer: $1,170ft^2$

Step-by-step explanation:

We know that the area of the living room can be calculated with the formula for find the area of a rectangle. This formula is:

$A_1=l_1*w_1$

Where:

$l_1$ is the lenght of the original living room, and $w_1$ is the width of the original living room.

If he creates the addition that causes the dimensions to triple, then the new area of Garrett’s living room is:

$A_2=(3l_1)(3w_1)\\A_2=(3*13ft)(3*10ft)\\A_2=1,170ft^2$

4 0

3 years ago

2.5_2.05 answer plz help

mezya [45]

Your answer is 0.45 I think

7 0

3 years ago

Read 2 more answers

Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero.

timama [110]

Answer:

hahahhaa thanks

Step-by-step explanation:

ahahahhahahad

5 0

2 years ago

Find the two odd integers which when squared and added together make the number 1994

Nostrana [21]

X^2 = 1994

x= + - sqrt (1994)

Unfortunately, there is no integer that can suit x.

3 0

2 years ago

A)Determine whether the sequence is divergent or convergent. If it is convergent, evaluate its limit. If it diverges to infinity

Colt1911 [192]

Answer:

a) The sequence converges to 0

b) The lenght of the curve is $\frac{1}{54}(217^{3/2}-37^{3/2})$

Step-by-step explanation:

Consider the sequence $a_n = \frac{-6n^6 + \sin^2(7n)}{n^7+11}$

a) We will prove it using the sandwich lemma. Note that for all n $-1\leq \sin^2(7n)\leq 1$ , then

$\frac{-6n^6 -1}{n^7+11}\leq\frac{-6n^6 + \sin^2(7n)}{n^7+11}\leq \frac{-6n^6 + 1}{n^7+11}$

Note that the expressions on the left and the right hand side have a greater degree on the denominator than the one on the numerator. Then, by takint the limit n goes to infinty on both sides, we have that

$0 \leq\frac{-6n^6 + \sin^2(7n)}{n^7+11} \leq 0$