Which equation is used to calculate the magnetic force on a charge moving in a magnetic field?

2 answers:

7 0

The force is perpendicular to the plane formed by v and B. Since the force is zero if v is parallel to B, charged particles often follow magnetic field lines rather than cross them.

B) F = |q|vBsin

katrin2010 [14]3 years ago

6 0

Answer: The correct option is (B).

Explanation:

The force on a charge moving in a magnetic field is as follows;

$F= qvBsin\theta$

Here, q is the charge, v is the velocity, B is the magnetic field and $\theta$ is the angle between the velocity and the magnetic field.

The magnetic force is perpendicular to both magnetic field and velocity. Its direction is determined by the right hand rule.

If the angle between the velocity and the magnetic field is 90 degree then the expression of the magnetic force becomes as;

$F= qvB$

Therefore, the correct option is (B).

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Which of the following is true about a planet orbiting a star in uniform circular

Mnenie [13.5K]

The velocity vector of the planet points toward the center of the circle is the following is true about a planet orbiting a star in uniform circular motion.

A. The velocity vector of the planet points toward the center of the circle.

<u>Explanation:</u>

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Thus at every point, the direction of velocity vector changes and this means the velocity is never constant. The objects in uniform circular motion has centripetal acceleration which means that velocity vector of the planet points toward the center of the circle.

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3 years ago

If you use a force of 90 N to pick up a 10 pound bag of charcoal, what is the acceleration?

hjlf

Answer:

9ms^2

Explanation:

since ,Force=mass*acceleration

then, acceleration=force/mass

and, Force=90N

Mass=10pound

therefore, acceleration=90/10