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balandron [24]
3 years ago
12

If a dog runs at 3 m/s for 20 seconds, how far did he run

Physics
2 answers:
umka2103 [35]3 years ago
4 0
60 m/s I think you multiply 3 times 20
prisoha [69]3 years ago
3 0
60 meters

20 x 3 =60

Brainliest?
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Calculate the magnitude of the angular momentum of the earth due its daily rotation about its own axis
ioda
L=Iw
I_{earth} =  \frac{2}{5} r^{2}m= \frac{2}{5} (6371000^2m)(5.97*10^{24}kg)=9.71*10^ {37}
L_{earth}=Iw=(9.71*10^ {37})(7.27*10^{-5})=7.07*10^{33}<span>[/tex]</span>

7 0
3 years ago
A car is moving South at a constant speed of 60 miles per hour. The force of the
Anastaziya [24]

Answer: 750 N

Explanation:

The net force is 1200 - 450 = 750 N

As we are told the speed is constant, then this force must be increasing the car's potential energy by climbing a hill.

F = mgsinθ

If we knew the car mass, we could find the hill slope angle.

If we knew the hill slope angle, we could find the car mass.

6 0
3 years ago
Which of the following is not a vector quantity?
maksim [4K]

Answer:

A. Speed

Explanation:

A vector quantity is a quantity which has both magnitude and direction. Here in the given options, speed is a scalar quantity but not the vector quantity.

7 0
3 years ago
If the mass of a material is 111 grams and the volume of the material is 23 cm3, what would the density of the material be? g/cm
Butoxors [25]
Density can be kg/m^3 or g/cm3
In g/cm3 density =mass /volume =111g/23cm3
=4.826g/cm3.

In kg/m3,density=mass/volume. converting mass in grams to kg, 1000g=1kg,111g=0.111kg.
cm3 to m3, 1cm3=10^-6m3, 23cm3=0.000023m3
density=0.111kg/0.000023m3 or 2.3*10^-5=4,826.1kg/m3.

the other is a long process.
4 0
3 years ago
A concave mirror has a focal length of 13.5 cm. This mirror forms an image located 37.5 cm in front of the mirror. Find the magn
77julia77 [94]

Explanation:

It is given that,

Focal length of the concave mirror, f = -13.5 cm

Image distance, v = -37.5 cm (in front of mirror)

Let u is the object distance. It can be calculated using the mirror's formula as :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}

\dfrac{1}{u}=\dfrac{1}{(-13.5)}-\dfrac{1}{(-37.5)}

u = -21.09 cm

The magnification of the mirror is given by :

m=\dfrac{-v}{u}

m=\dfrac{-(-37.5)}{(-21.09)}

m = -1.77

So, the magnification produced by the mirror is (-1.77). Hence, this is the required solution.

7 0
3 years ago
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