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3 years ago

Your favorite taco stand is 800 m away, and closes in 15 minutes. How fast do you have to run to make it on

Physics

2 answers:

Dimas [21]3 years ago

8 0

You must run at least 53.3333333 meters a minute.

ValentinkaMS [17]3 years ago

6 0

To find the rate that you need to run, you should do distance/time

So, 800/15=53.33. You have to run at 53.33meters per minute to make it on time

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I will mark you brainlist!

Dima020 [189]

Answer:

Human activities commonly affect the distri-

bution, quantity, and chemical quality of water

resources. The range in human activities that affect

the interaction of ground water and surface water is

broad.Explanation:

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3 years ago

while test flying the new f-22 raptor fighter jet, test pilot bob put the plane in a horizontal loop while flying at the speed o

sveticcg [70]

Given

v = 343 m/s

ac = 5g

ac = 5*9.8 m/s^2

ac = 49 m/s^2

where,

v: velocity

ac = centripetal aceleration

Procedure

We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration ac; centripetal means “toward the center” or “center seeking”.

Formula

$\begin{gathered} a_c=\frac{v^2}{r} \\ r=\frac{v^2}{a_c} \\ r=\frac{(343m/s)^2}{49m/s^2} \\ r=2401\text{ m} \end{gathered}$

The minimum radius not to exceed the centripetal acceleration is 2401 m.

8 0

2 years ago

A 0.200-kg mass is attached to the end of a spring with a spring constant of 11 N/m. The mass is first examined (t = 0) when the

inn [45]

Answer:

a) x (t) = 0.3187 cos (7.416 t + 1.008) , b) v = -2,363 sin (7,416 t + 1,008)

c) a = - 17.52 cos (7.416t + 1.008)

Explanation:

The spring mass system creates a harmonic oscillator that is described by the equation

x = Acos (wt + φ)

Where is the amplitude, w the angular velocity and fi the phase

a) Let's reduce the SI system

x = 17.0 cm (1 m / 100 cm) = 0.170 m

The angular velocity is given by

w = √ (k / m)

w = √ 11 / 0.200

w = 7.416 rad / s

Let's look for the terms of the equation with the data for time zero (t = 0 s)

0.170 = A cos φ

Body speed can be obtained by derivatives

v = dx / dt

v = -A w sin (wt + φ)

2.0 = -A 7.416 sin φ

Let's write the two equations

0.170 = A cos φ

2.0 / 7.416 = -A sin φ

Let's divide those equations

tan φ= 2.0 / (7.416 0.170)

φ= tan⁻¹ (1,586)

φ= 1.008 rad

We calculate A

A = 0.170 / cos φ

A = 0.170 / cos 1.008

A = 0.3187 m

With these values we write the equation of motion

x (t) = 0.3187 cos (7.416 t + 1.008)

b) the speed can be found by derivatives

v = dx / dt

v = - 0.3187 7.416 sin (7.416 t +1.008)

v = -2,363 sin (7,416 t + 1,008)

c) the acceleration we look for conserved

a = dv / dt

a = -2,363 7,416 cos (7,416 t + 1,008)

a = - 17.52 cos (7.416t + 1.008)

6 0

3 years ago

What happens when an electron moving from the 3rd energy level to the 1st energy level?

Sholpan [36]

Answer:

A photon of wavelength 103 nm is released

Explanation:

When an electron in an atom jumps from a higher energy level to a lower energy level, it releases a photon whose energy is equal to the difference in energy between the two levels.

For example, if we are talking about a hydrogen atom, the energy of the levels are:

$E_1 = -13.6 eV\\E_2 = -3.4 eV\\E_3 = -1.5 eV$

So, the energy of the photon released when the electron jumps from the level n=3 to n=1 is

$\Delta E = E_3 - E_1 = -1.5 -(-13.6)=12.1 eV$

In Joules,

$\Delta E =12.1\cdot 1.6\cdot 10^{-19} = 1.94\cdot 10^{-18} J$

We can also find the wavelength of this photon, using the equation:

$\Delta E = \frac{hc}{\lambda}\rightarrow \lambda=\frac{hc}{\Delta E}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{1.94\cdot 10^{-18}}=1.03\cdot 10^{-7} m = 103 nm$