The resistance of a given conductor depends on its electrical resistivity (
), its length(L) and its cross-sectional area (A), as follows:
![R=\frac{\rho L}{A}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B%5Crho%20L%7D%7BA%7D)
In this case, we have
,
and
. So, the total resistance of the wire with length of 138m is:
![R'=\frac{\rho' L'}{A'}\\R'=\frac{\rho 138L}{A}\\R'=138\frac{\rho L}{A}\\R'=138R\\R'=138(0.24\Omega)\\R'=33.12\Omega](https://tex.z-dn.net/?f=R%27%3D%5Cfrac%7B%5Crho%27%20L%27%7D%7BA%27%7D%5C%5CR%27%3D%5Cfrac%7B%5Crho%20138L%7D%7BA%7D%5C%5CR%27%3D138%5Cfrac%7B%5Crho%20L%7D%7BA%7D%5C%5CR%27%3D138R%5C%5CR%27%3D138%280.24%5COmega%29%5C%5CR%27%3D33.12%5COmega)
That would be Cyanide.
Hope this helps! (:
The mass of the aeroplane is 300,000 kg.
<h3>What is Newton's second law of motion?</h3>
It states that the force F is directly proportional to the acceleration a of the body and its mass.
The law is represented as
F =ma
where acceleration a = velocity change v / time interval t
Given is the aeroplane lands at a speed of 80 m/s. After landing, the aeroplane takes 28 s to decelerate to a speed of 10 m/s. The mean resultant force on the aeroplane as it decelerates is 750 000 N.
The force expression will be
F = mv/t
Substitute the values and we have
750000 = m x (80 -10)/ 28
750,000 = m x 2.5
m = 300,000 kg
Thus, the mass of the aeroplane is 300,000 kg.
Learn more about Newton's second law of motion.
brainly.com/question/13447525
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Answer:
a)![T = 2.9*10^{-5} N-m](https://tex.z-dn.net/?f=T%20%3D%202.9%2A10%5E%7B-5%7D%20N-m)
b) north edge will rise up
Explanation:
torque on the coil is given as
![T = NIABsin\theta](https://tex.z-dn.net/?f=T%20%3D%20NIABsin%5Ctheta)
where N is number of loop = 9 loops
i is current = 7.80 A
-B -earth magnetic field = ![5.00*10^{-5} T](https://tex.z-dn.net/?f=5.00%2A10%5E%7B-5%7D%20T)
A- area of circular coil
![A = \frac{\pi d^{2}}{4}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B%5Cpi%20d%5E%7B2%7D%7D%7B4%7D)
![A =\frac{\pi .14^{2}}{4}](https://tex.z-dn.net/?f=A%20%3D%5Cfrac%7B%5Cpi%20.14%5E%7B2%7D%7D%7B4%7D)
A =0.015 m2
PUTITNG ALL VALUE TO GET TORQUE
![T = 9*7.8*0.015*5*10^{-5} sin{90-56}](https://tex.z-dn.net/?f=T%20%3D%209%2A7.8%2A0.015%2A5%2A10%5E%7B-5%7D%20sin%7B90-56%7D)
![T = 2.9*10^{-5} N-m](https://tex.z-dn.net/?f=T%20%3D%202.9%2A10%5E%7B-5%7D%20N-m)
b) north edge will rise up