A 1.0 kg piece of copper with a specific heat of cCu=390J/(kg⋅K) is placed in 1.0 kg of water with a specific heat of cw=4190J/(
1 answer:
Answer:
The temperature change of the copper is greater than the temperature change of the water.
Explanation:
deltaQ = mc(deltaT)
Where,
delta T = change in the temperature
m =mass
c = heat capacity
The temperature change in the copper is nearly 11 times the temperature change in the water.
So, the correct option is,
The temperature change of the copper is greater than the temperature change of the water.
Hope this helps!
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The true statement about the CD is:
<h3><em>b. No net torque acts on it at all.</em></h3>Centripetal Acceleration can be formulated as follows:
<em>a = Centripetal Acceleration ( m/s² )</em>
<em>v = Tangential Speed of Particle ( m/s )</em>
<em>R = Radius of Circular Motion ( m )</em>
Centripetal Force can be formulated as follows:
<em>F = Centripetal Force ( m/s² )</em>
<em>m = mass of Particle ( kg )</em>
<em>v = Tangential Speed of Particle ( m/s )</em>
<em>R = Radius of Circular Motion ( m )</em>
Let us now tackle the problem !
<em>Complete Question:</em>
<em>A CD spins at a constant angular velocity of 5.0 revolutions per second clockwise. Which of the following statements about the CD is true?</em>
<em>a. A net torque acts on it clockwise to keep it moving</em>
<em>b. No net torque acts on it at all.</em>
<em>c. A net torque acts on it counterclockwise to keep it moving</em>
<u>Given:</u>
angular velocity = ω = 5.0 revolutions per second
<u>Asked:</u>
net torque = Στ = ?
<u>Solution:</u>
Constant angular velocity → angular acceleration = α = 0 rad/s²
The true statement about the CD is:
<em>b. No net torque acts on it at all.</em>
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Grade: High School
Subject: Physics
Chapter: Circular Motion
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
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Answer:
a)
b)
c)
d)
Explanation:
Average translation kinetic energy () is given as
....................(1)
where,
k = Boltzmann's constant ; 1.38 × 10⁻²³ J/K
T = Temperature in kelvin
a) at T = 27.8° C
or
T = 27.8 + 273 = 300.8 K
substituting the value of temperature in the equation (1)
we have
b) at T = 143° C
or
T = 143 + 273 = 416 K
substituting the value of temperature in the equation (1)
we have
c ) The translational kinetic energy per mole of an ideal gas is given as:
here = Avagadro's number; ( 6.02×10²³ )
now at T = 27.8° C
d) now at T = 143° C