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gavmur [86]
3 years ago
13

You drop a ball at 27 feet high. How long will it take for the ball to hit the ground?

Physics
1 answer:
ivolga24 [154]3 years ago
6 0

Ball will hit the ground after a time of 1.296 s

Explanation:

initial velocity of ball= Vi=0

g= 9.8 m/s²

height =h= 27 ft=8.23 m

using the kinematic equation

h= Vi t + 1/2 gt²

8.23=0(t) + 1/2 (9.8)t²

t²=1.6796

t=1.296 s

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How does the momentum of a fast object compare to that of a slow object if they both have the same mass?
Varvara68 [4.7K]
The momentum of a fast object compared to that of a slow object even if they both have the same mass, is their velocities.

Having same mass but different velocities results in different momentum.

Example: mass = 10kg
Velocity 1 = 50 Velocity 2 = 100
Momentum 1 = 10×50 = 500 Ns
Momentum 2 = 10×100 = 1000 Ns

Hope it helped!
3 0
3 years ago
What is the transfer of energy to an object using a force that causes the object to move in the direction of the force?
anastassius [24]
C. Work
w = f \times d
*Work is measured in Joules.
4 0
3 years ago
Sounds travel faster in Question 1 options: warmer air. cooler air. Temperature does not influence the speed of sound. a vacuum.
olya-2409 [2.1K]

Answer:

warmer air

Explanation:

the particles are more excited which increases the probability that the particles will bump into each other

8 0
2 years ago
What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A
MrRa [10]

Answer:

15.34 kVA

Explanation:

A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.

The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.

Hence Power (P) =√3 × voltage (V) × current (I)

P = √3 × V × I

Given that voltage (V) = 460 V, current (I) = 17 A. Hence:

P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA

But 1000 VA = 1 kVA. Hence:

P=13544.64\ VA*\frac{1\ kVA}{1000\ VA}=13.54\ kVA

8 0
3 years ago
Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the p
PSYCHO15rus [73]

Answer:

Energy density will be 14.73 J/m^3

Explanation:

We have given capacitance C=225\mu F=225\times 10^{-6}F

Potential difference between the plates = 365 V

Plate separation d = 0.200 mm 0.2\times 10^{-3}m

We know that there is relation between electric field and potential

E=\frac{V}{d}, here E is electric field, V is potential and d is separation between the plates

So E=\frac{V}{d}=\frac{365}{0.2\times 10^{-3}}=1825000N/C

Energy density is given by E=\frac{1}{2}\varepsilon _0E^2=\frac{1}{2}\times 8.85\times 10^{-12}\times (1.825\times 10^6)^2=14.73J/m^3

5 0
3 years ago
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