Answer:
The intensity level of the sound wave due to the ambulance is 153.5 dB.
Explanation:
The intensity level of the sound wave due to the ambulance can be calculated using the following equation:

<u>Where</u>:
I: is the intensity of the sound wave from a siren = 111.2 W/m²
I₀: is the reference intensity = 1.0x10⁻¹² W/m²
Now, since the second sound wave from a nearby ambulance has an intensity level 13 dB we have:

Therefore, the intensity level of the sound wave due to the ambulance is 153.5 dB.
I hope it helps you!
Answer:
Explanation:
Given
Airplane is flying with horizontally with a constant momentum during time interval 
Impulse is given by change in momentum, so there is no net impulse on the Plane because momentum is constant
(b) As there is no change in momentum therefore impulse of thrust and air drag is balanced i.e. both are equal in magnitude but act in opposite direction
Answer:
The track's angular velocity is W2 = 4.15 in rpm
Explanation:
Momentum angular can be find
I = m*r^2
P = I*W
So to use the conservation
P1 + P2 = 0
I1*W1 + I2*W2 = 0
Solve to w2 to find the angular velocity
0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2
W2 = 0.435 rad/s
W2 = 4.15 rpm