Answer:
2.56 N*m
Explanation:
Torque is force times distance, with the force being perpendicular to the distance.
If the force and distance are not perpendicular, a projection of one of the two must be used instead.
We will use the projection of the length of the shaft upon a perpendicular of the force applied. This will have a magnitude of:
Lh = L * cos(a) (I name it Lh because it is a horizontal projection in this case)
Lh = 0.2 * cos(π/5) = 0.16 m
Then:
T = f * d
T = 16 * 0.16 = 2.56 N*m
It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.
To find the answer, we need to know about the third law of Kepler.
<h3>What's the Kepler's third law?</h3>
- It states that the square of the time period of orbiting planet or satellite is directly proportional to the cube of the radius of the orbit.
- Mathematically, T²∝a³
<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>
- The time period of geosynchronous orbit is 24 hours or 1440 minutes.
- As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
- If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
- a1= (T1/T2)⅔×a2
= (1440/90)⅔×6780
= 43,090 km
- Altitude of geosynchronous orbit = 43,090 - 6371= 36,719 km
Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.
Learn more about the Kepler's third law here:
brainly.com/question/16705471
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Using the Pythagorean’s theorem to find the resultant, we find 5’2 +3’2=x’2
X=square root of 34=5.8unitd
Answer:
Dopamine
Explanation:
schizophrenia is caused by an overactive dopamine system in the brain
Answer:
Force due to tension
Explanation:
Usually Ft, or F
, denotes force due to tension or tension force. An example of tension force would be if you were pulling an object on a string - the tension force is present within the string and causes the string not to break.
