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3 years ago

PLEASE HELPP MEEE!!!!!!!!!The goal is to increase the power; therefore, it is necessary to

Physics

2 answers:

Novay_Z [31]3 years ago

4 0

Answer: The answer would be C

Explanation:

Brrunno [24]3 years ago

3 0

As we know that power is defined as rate of work done

so we will have

$P = \frac{Work}{time}$

so in order to increase the power as per above formula we know that either we need to increase the work or we need to decrease the time to complete that work

So here the correct answer will be

increase the work being done or decrease the time in which the work is completed.

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A quantum well is a region of semiconductor or metal film that confines particles to a small region, resulting in quantized ener

murzikaleks [220]

Answer:

226.2 m/sec

Explanation:

We have given $\Delta x=510nm=510\times 106{-9}m$

The plank's constant $h=6.67\times 10^{-34}$

Mass of electron $m=9.11\times 10^{-31}kg$

Now according to Heisenberg uncertainty principle $\Delta v\geq \frac{h}{2\pi m\Delta x}$

So $\Delta v\geq \frac{6.6\times 10^{-34}}{2\times 3.14\times 9.11\times 10^{-31}\times 510\times 10^{-9}}=226.2m/sec$

5 0

3 years ago

All of the following show friction as a useful force, except _____.

prohojiy [21]

Answer: having to push a rough and heavy box across the floor to move it

Explanation:

The Friction force is any force that is in opposite direction of the motion of an object or fluid due to the contact of this object or fluid with other bodies.

In this sense, there are different types of friction force thath are useful in different situations:

-The <u>Static friction force</u> prevents surfaces from slipping across each other. For example, the friction between your feet and the floor keeping you from slipping.

-The <u>kinetic friction force</u> as the force that helps the tires in a moving vehicle to slow down and stop when necessary.

However, if you want to push a heavy box across the floor to move it, the friction force will not be useful at all.

6 0

3 years ago

Read 2 more answers

5.1C A fluid flows steadily through a pipe with a uniform crosssectional area. The density of the fluid decreases to half its in

prisoha [69]

The options are;

a. V2 equals 2V1.

b. V2 equals (V1)/2.

c. V2 equals V1.

d. V2 equals (V1)/4.

e. V2 equals 4V1.

Answer:

Option A: V2 equals 2V1

Explanation:

Since the flow is steady, then we can say;

mass flow rate at input = mass flow rate at output.

Formula for mass flow rate is;

m' = ρVA

Thus;

At input;

m'1 = ρ1•V1•A1

At output;

m'2 = ρ2•V2•A2

So, m'1 = m'2

Now, we are told that the density of the fluid decreases to half its initial value.

Thus; ρ2 = (ρ1)/2

Since m'1 = m'2, then;

ρ1•V1•A1 = (ρ1)/2•V2•A2

Now, the pipe is uniform and thus the cross section doesn't change. Thus;

A1 = A2

We now have;

ρ1•V1•A1 = (ρ1)/2•V2•A1

A1 and ρ1 will cancel out to give;

V1 = (V2)/2

Thus, V2 = 2V1

5 0

2 years ago

Infrared light of wavelength 2.5 µm illuminates a 0.20-mm-diameter hole. What is the angle of the first dark fringe in radians?

stepan [7]

Answer:

Θ=0.01525 rad

Θ=0.87°

Explanation:

Given data

wavelength λ=2.5 µm =2.5×10⁻⁶m

Diameter d=0.20 mm =0.20×10⁻³m

To find

Angle Θ in radians and degree

Solution

Circular apertures have first dark fringe at

Θ=(1.22λ)/d

Substitute the given values

Θ=[1.22(2.5×10⁻⁶m)]/0.20×10⁻³m

Θ=0.01525 rad

Θ=0.87°

6 0

3 years ago

How can you say metre cube is a derived unit

riadik2000 [5.3K]

Answer:

The newton (lowercase n!) is a derived unit because its definition consists of multiplication of three defined base units and nothing else. Its meaning is thus derived, not independently defined.

8 0

2 years ago