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3 years ago

9

Compare and contrast formation of with the formation of mgcl2

1 answer:

zalisa [80]3 years ago

3 0

Answer: Both of the compounds contain primary bonding; however, the bonding is of different types. Magnesium chloride (MgCl₂) contains ionic bonds, which are stronger and involve the complete transfer of electrons. Meanwhile, ethane (C₂H₆) also bonds by electron transfer but the electrons are not completely transferred from one atom to another. Instead, they are shared, forming what is known as a covalent bond.

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A pulse traveled the length of a stretched spring the pulse transferred...A)energy only B)mass only C)both energy and mass D) ne

xz_007 [3.2K]

Answer:

A

Explanation:

So a pulse is a part of a mechanical wave, and mechanical waves are energy transfer trough some medium, in this case a stretched spring. So the correct answer is (A) energy only. The pulse cant be transferred into mass.

8 0

3 years ago

A uranium and iron atom reside a distance R = 44.10 nm apart. The uranium atom is singly ionized; the iron atom is doubly ionize

Ad libitum [116K]

Answer:

distance r from the uranium atom is 18.27 nm

Explanation:

given data

uranium and iron atom distance R = 44.10 nm

uranium atom = singly ionized

iron atom = doubly ionized

to find out

distance r from the uranium atom

solution

we consider here that uranium electron at distance = r

and electron between uranium and iron so here

so we can say electron and iron distance = ( 44.10 - r ) nm

and we know single ionized uranium charge q2= 1.602 × $10^{-19}$ C

and charge on iron will be q3 = 2 × 1.602 × $10^{-19}$ C

so charge on electron is q1 = - 1.602 × $10^{-19}$ C

and we know F = $k\frac{q*q}{r^{2} }$

so now by equilibrium

Fu = Fi

$k\frac{q*q}{r^{2} }$ = $k\frac{q*q}{r^{2} }$

put here k = $9*10^{9}$ and find r

$9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{r^{2} }$ = $9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{(44.10-r)^{2} }$

$\frac{1}{r^{2} } = \frac{2}{(44.10 -r)^2}$

r = 18.27 nm

distance r from the uranium atom is 18.27 nm

6 0

3 years ago

Two pebbles are dropped into a pool of water as shown. If a new wave with a

Kazeer [188]

Answer:

Constructive interference

Explanation:

3 0

3 years ago

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Calculate the number of moles in 100g of water

dsp73

5.55 mol H2O

Explanation:

Water has a molar mass of 18.01528 g/mol. We can then calculate the number of moles of water as

100 g H20 × (1 mol H2O/18.01528 g H20)

= 5.55 mol H2O

5 0

3 years ago

A box of mass m1 rests on a smooth, horizontal floor next to a box of mass m2. Suppose the force of 20.0 N pushes on two boxes o

meriva

Answer:

Explanation:

Given

acceleration of system a =1.2 m/s^2

Normal Force N=4.45 N

Force exerted F=20 N

Thus

$F=(m_1+m_2)a$

$\frac{20}{1.2}=m_1+m_2$

$16.67=m_1+m_2$ -------1

Normal reaction $N=m_2a$

$4.45=m_2\times 1.2$

$m_2=3.70 kg$

therefore $m_1=16.67-3.70$

$m_1=12.96 kg$

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3 years ago

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