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vladimir2022 [97]
3 years ago
5

3ewhgaxjbhnkm4rewbs nkm11 what's 1+ 10 ?

Mathematics
2 answers:
saul85 [17]3 years ago
6 0

Answer:

its 11

Step-by-step explanation:

1+ 10= 11 just add 1 hope it helps.

Juli2301 [7.4K]3 years ago
5 0

Answer:

11

Step-by-step explanation:

lol 1+10=11

I had to process the question for a few sec for some reason.

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Suki is using 25 apples for her crumble.
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Match each figure with the number of edges it has.
Rashid [163]

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Rectangular prism- 12 edges

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6 0
3 years ago
-8(8v + 1) - 2 = -394
Bess [88]

Answer:

v = 6

Step-by-step explanation:

Solve for v:

-8 (8 v + 1) - 2 = -394

-8 (8 v + 1) = -64 v - 8:

-64 v - 8 - 2 = -394

Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):

-64 v + (-8 - 2) = -394

-8 - 2 = -10:

-10 - 64 v = -394

Add 10 to both sides:

(10 - 10) - 64 v = 10 - 394

10 - 10 = 0:

-64 v = 10 - 394

10 - 394 = -384:

-64 v = -384

Divide both sides of -64 v = -384 by -64:

(-64 v)/(-64) = (-384)/(-64)

(-64)/(-64) = 1:

v = (-384)/(-64)

The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:

Answer:  v = 6

3 0
3 years ago
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How do i calculate the first quartile and the third quartile??? <br> !!!please help!!!
diamong [38]

Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99

Step-by-step explanation: Ok, so let's put the data set from least to greatest....

(63, 63, 76,) (77, 79,) (84, 99, 99)

First Quartile              Third Quartile

First, let's find the median, since you made a little mistake...

77 + 79 = 156

156 ÷ 2 = 78

The median is 78!

Now, let's determine the first quartile and the third quartile.

For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...

First Quartile: 63

Third Quartile: 99

I hope this helps!

5 0
3 years ago
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