Newton taught us that Force = (mass) x (acceleration)

Force = (0.2) x (20) = <em>4 newtons</em> .

Something to think about: The ball can only accelerate while the club-face
is in contact with it. Once the ball leaves the club, it can't accelerate any more,
because the force against it is gone.

4 0

3 years ago

. Starting from a stop at a traffic signal, a car speeds up to 20 m/s in 5 seconds. Calculate the acceleration of the car.

Dimas [21]

Answer: 4m/s²

Explanation:

At stop signal car speed iz 0 ; V1=0m/s

After t=5s , car has speed is V2=20m/s

using:

a=(V2-V1)/t

a=(20m/s-0m/s)/5s

a=20m/s/5s

a=4m/s²

4 0

3 years ago

Two identical masses are attached to two identical springs that hang vertically. The two masses are pulled down and released, bu

Alex17521 [72]

Answer:

Lets take mass of A = m

Mass of B = m

Lets take spring constant = K

Displacement of mass A = x

Displacement of mass B= x'

Given that

x ' > x

We know that time period of spring mass system given as

$T= 2\pi\sqrt{\dfrac{m}{K}}$

Time does not depends on the displacement.

So time will be same for both.

We know that acceleration given as

a= ω² .x

ω=natural frequency ( ω² = m K)

Here x ' > x

So Acceleration of mass B is greater than mass A.

Velocity at equilibrium position

V= ω .x

Here x ' > x

So velocity of mass B is greater than mass A.

As we know that at equilibrium point acceleration of the mass is zero.So both the mass have same acceleration and the value of this acceleration will be zero m/s².

3 0

3 years ago