<u>Answer:</u> The mass percent of hydrogen in methyl acetate is 8 %
<u>Explanation:</u>
The given chemical formula of methyl acetate is 
To calculate the mass percentage of hydrogen in methyl acetate, we use the equation:
Mass of hydrogen = (6 × 1) = 6 g
Mass of methyl acetate = [(3 × 12) + (6 × 1) + (2 × 16)] = 74 g
Putting values in above equation, we get:
Hence, the mass percent of hydrogen in methyl acetate is 8 %
4p, 3d, 3p, 3s, 2p, 2s and 1s orbitals may be occupied during de-excitation.<span />
Answer:
The answer to your question is V2 = 23.52 l
Explanation:
Data
Volume 1 = V1 = 22.5 l
Pressure 1 = P1 = 734 mmHg
Volume 2 = V2 = ?
Pressure 2 = 702 mmHg
Process
To solve this problem use Boyle's law.
P1V1 = P2V2
-Solve for V2
V2 = P1V1 / P2
-Substitution
V2 = (734 x 22.5) / 702
-Simplification
V2 = 16515 / 702
-Result
V2 = 23.52 l
-Conclusion
If we diminish the pressure, the volume will be higher.
Hey there!:
The hydroxyl groups act to neutralize the sodium borohydride which reduces yield.
Hope that helps!
Answer:
d. n = 4, l = 2, m = 0
Explanation:
A d-orbital in the fourth energy level can only be represented by n = 4, l = 2, m = 0.
n is the principal quantum number(n) which signifies the energy level, here it is 4;
l is the azimuthal quantum number or l which signifies the shape of the subshell, it takes a value of n - 1, 0,1,2 or 3
m is the magnetic quantum number(m) which can be -2, -1, 0, 1 , 2
So, the right and fitting solution is n = 4, l = 2, m = 0
