Answer:
469.875 square feet
Step-by-step explanation:
All you have to do for this question is multiply 3.75 bags of soil * 125.3 feet per bag.
square feet
Answer:
Positive: Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is always greater than a negative decimal.
Negative: When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.
All of it put together (same text as above):
Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is ALWAYS greater than a negative decimal. When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.
Answer is B because the red has 2 columns and 7 rows that is how you get 2/7 And the blue has 3 rows and 5 columns making 3/5
If you multiply these together you get the doubled colored (red/blue over the total of squares)
6/35
The other way which most likely I think you should choose this way is D why?? Because there are out of the red are 3 out of 7 rows that are combined with blue and 2 out of 5 of the blue column are combined with red
This makes the 3/7×2/5 = with the 6/35 (combined colors/total)
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
Factors of 35: 1, 5, 7, 35
Of those, only 5 and 7 are prime.
7>5
Final answer: 7
