Answer: Force applied by trampoline = 778.5 N
<em>Note: The question is incomplete.</em>
<em>The complete question is : What force does a trampoline have to apply to a 45.0 kg gymnast to accelerate her straight up at 7.50 m/s^2? note that the answer is independent of the velocity of the gymnast. She can be moving either up or down or be stationary.
</em>
Explanation:
The total required the trampoline by the trampoline = net force accelerating the gymnast upwards + force of gravity on her.
= (m * a) + (m * g)
= m ( a + g)
= 45 kg ( 7.50 * 9.80) m/s²
Force applied by trampoline = 778.5 N
I think It would be C. Checking a prediction. Sorry if I’m wrong
Answer:A
Explanation:
It’s bigger I am not sure
Answer:
(a): 
(b): 
(c): 
Explanation:
Given that an electron revolves around the hydrogen atom in a circular orbit of radius r = 0.053 nm = 0.053
m.
Part (a):
According to Coulomb's law, the magnitude of the electrostatic force of interaction between two charged particles of charges 
and 
respectively is given by
where,
= Coulomb's constant = 
= distance of separation between the charges.
For the given system,
The Hydrogen atom consists of a single proton, therefore, the charge on the Hydrogen atom, 
The charge on the electron, 
These two are separated by the distance, 
Thus, the magnitude of the electrostatic force of attraction between the electron and the proton is given by
Part (b):
The gravitational force of attraction between two objects of masses 
and respectively is given by
where,
= Universal Gravitational constant = 
- = distance of separation between the masses.
For the given system,
The mass of proton, 
The mass of the electron, 
Distance between the two,
Thus, the magnitude of the gravitational force of attraction between the electron and the proton is given by
The ratio 
:
<h3>
Answer: 104.5 cubic cm</h3>
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Work Shown:
r = radius = 1.045 cm
h = height = 30.48 cm
pi = 3.141 approximately
V = volume of cylinder
V = pi*r^2*h
V = 3.141*(1.045)^2*30.48
V = 104.547940002
V = 104.5 cubic cm
