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Liono4ka [1.6K]
3 years ago
6

Air at 38oC and 97% relative humidity is to be cooled to 14oC and fed into a plant area at a rate of 510 m3/min. Calculate the r

ate (kg/min) at which water condenses. (Round the answer to the nearest whole number)
Physics
1 answer:
bekas [8.4K]3 years ago
8 0

Answer:

mass flow rate at  water condenses is 36.72 kg/min

Explanation:

given data

temperature t1 = 38°C

temperature t2 = 14°C

humidity ∅= 97 % = 0.97

rate v = 510 m³/min

to find out

mass flow rate at  water condenses

solution

by gas equation we find here mass flow rate  that is

pv = mRT

put here value and p is 0.066626 bar at 38°C and find m

m = 0.06626 × 10^{5} × 510  / 287×311

m = 37.85 kg/min

so at water condenses mass flow rate is express as

∅ = M / m

Mass flow rate M = ∅ × m

M = 0.97 × 37.85

mass flow rate = 36.72 kg/min

so mass flow rate at  water condenses is 36.72 kg/min

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Write an expression for a harmonic wave with an amplitude of 0.19 m, a wavelength of 2.6 m, and a period of 1.2 s. The wave is t
zlopas [31]

Answer:

y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})

Explanation:

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y = A sin(\omega t - k x + \phi_0)

now we have

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