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Zigmanuir [339]
3 years ago
15

A proposed space station includes living quarters in a circular ring 45.0 m in diameter.

Physics
1 answer:
siniylev [52]3 years ago
6 0

Answer:

Angular speed, \omega=0.65\ rad/s

Explanation:

Given that,

Diameter of the circular ring, D = 45 m

Radius, r = 22.5 m

Let \omega is the angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth. It can be given by providing the centripetal force to the normal force as :

mg=m\omega^2r

\omega=\sqrt{\dfrac{g}{r}}

\omega=\sqrt{\dfrac{9.8\ m/s^2}{22.5\ m}}

\omega=0.65\ rad/s

So, the angular speed of the ring is 0.65 rad/s. Hence, this is the required solution.

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A long wire carrying a 5.8 A current perpendicular to the xy-plane intersects the x-axis at x=−2.3cm. A second, parallel wire ca
adoni [48]

Answer:

a) v    r = 0.7318 cm , b)  r = 7.23 cm

Explanation:

The magnetic field generated by a wire carrying a current can be found with Ampere's law

       ∫ B. ds = μ₀ I

the length of a surface circulates around the wire is

    s = 2π r

where r is the point of interest of the calculation of the magnetic field

         B = μ₀ I / 2π r

In this exercise we have two wires, write the equation of the magnetic field of each one

wire 1     I = 5.8 A

         B₁ = μ₀ 5,8 / 2π r₁

wire 2    I = 3.0 A

         B₂ = μ₀ 3/2π r₂

the direction of the field is given by the rule of the right hand, the thumb indicates the direction of the current and the other fingers the direction of the magnetic field

Let's apply these expressions to our case

a) the two streams go in the same direction

     using the right hand rule for each wire we see that between the two wires the magnetic fields have opposite directions so there is some point where the total value is zero

          B₁ - B₂ = 0

           B₁ = B₂

         μ₀ 5,8 / 2π r₁ = μ₀ 3 / 2π r₂

          5.8 / r₁ = 3 / r₂

          5.8 r₂ = 3r₁

the value of r is measured from each wire, therefore

        r₁ = 2.3 + r

        r₂ = 2.3 -r

we substitute

          5.8 (2.3 - r) = 3 (2.3 + r)

           r (3 + 5.8) = 2.3 (5.8 - 3)

           r = 2.3 2.8 / 8.8

           r = 0.7318 cm

b) the two currents have directional opposite

with the right hand rule in the field you have opposite directions outside the wires

suppose it is zero on the right side where the wire with the lowest current is

         B₁ = B₂

        5.8 / r₁ = 3 / r₂

        5.8 r₂ = 3 r₁

         r₁ = 2.3 + r

         r₂ = r - 2.3

        5.8 (r - 2.3) = 3 (2.3 + r)

        r (5.8 -3) = 2.3 (3 + 5.8)

        r = 2.3 8.8 / 2.8

        r = 7.23 cm

8 0
3 years ago
Identify the action and reaction forces in the following situations: a) Earth attracts the Moon, b) a boy kicks a football, c) a
jeka94

Answer:

#See solution for details

Explanation:

a. Action: Earth pulls on the Moon, reaction: Moon pulls on Earth;

b. Action: foot applies force to ball, reaction: ball applies force to foot;

c. Action: rocket pushes on gas, reaction: gas pushes back on rocket;

d. Action: car tires push backward on road, reaction: road pushes forward on tires;

e. Action: jumper pushes down on ground, reaction: ground pushes up on jumper;

f. Action: gun pushes forward on bullet, reaction: bullet pushes backward on gun

7 0
3 years ago
How can doing work on an object increase its kinetic energy?
Lyrx [107]

Answer:If the object's speed increases.

Explanation:

If the object's speed increases, then its kinetic energy will increase. If the kinetic energy increases, the change in kinetic energy will be positive.

6 0
3 years ago
A(n) 1.3 kg mass sliding on a frictionless surface has a velocity of 7.1 m/s east when it undergoes a one-dimensional elastic co
Oxana [17]

Answer: 2.12 kg

Explanation:

Since the 1.3 kg object moves to the west after the collision, the other object will move to the east after the collision.

In an elastic collision, the relative velocity after the collision is the opposite of the relative velocity before the collision. Since the 1.3 kg object’s velocity before the collision is 6.7 m/s greater than the other object, after the collision, its velocity will be 6.7 m/s less than the other object. To determine the other object’s velocity, use the following equation.

v = 1.7 – 7.1 = -5.4 m/s

The negative sign means it is moving eastward. Let’s use this number is a momentum equation to determine its mass.

Initial momentum = 1.3 * 7.1 = 9.23 east

For the 1.3 object, final momentum = 1.3 * 1.7 = 2.21 west

To determine the final momentum of the other object, add these two numbers.

Final momentum = 11.44 east

To determine its mass, use the following equation.

m * 5.4 = 11.44

m = 11.44 ÷ 5.4 = 2.12 kg

To make sure that kinetic energy is conserved, let’s round this number to 2 kg and determine the final kinetic energies.

For the 1.3 object, KE = 1/2 * 1/3* 1.7^2 = 0.48

For the 2 kg object, KE = 1/2* 2 * 5.4^2 = 29.64

Total final KE = 29.64

Initial KE = 0.5* 1.3 * 7.1^2 = 32.77

Since I rounded the mass up to 2kg, this proves that kinetic energy is conserved and the mass is correct!

3 0
3 years ago
Significant digits show the _____ of measurements and calculations.
SashulF [63]
Significant digits show the precision of measurements and calculations
7 0
3 years ago
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