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2 years ago

6

Two conductors made of the same material are connected across the same potential difference. Conductor A has three times the dia

meter and three times the length of conductor B. What is the ratio of the power delivered to A to the power delivered to B?

1 answer:

Vitek1552 [10]2 years ago

5 0

Answer:

<em>Good Luck!</em>

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Explanation:

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A 1000 kg truck moving at 2.0 m/s runs into a concrete wall. It takes 0.5 s for the truck to completely stop. What is the magnit

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Answer:

Momentum is given by

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I

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and is also equal to force times time:

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Explanation:

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Assuming the truck comes to a complete halt, the momentum after the collision is

0

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The change in momentum,

Δ

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→

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−

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,

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=

−

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I

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. Impulse is also equal (check the units) to force times time:

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We can rearrange this expression to make

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the subject:

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The negative sign just means the force acting is in the opposite direction to the initial momentum.

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What action force is used when sitting down

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When sitting down there is gravity , when sat down the chair is pushing back at a equal but opposite force

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An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If y

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Answer:

The fraction of the protons would have no electrons $=1.88\times 10^{-10}$

Explanation:

We are given that

Amoeba has total number of protons= $1.00\times 10^{16}$

Net charge, Q=0.300pC

Electrons are fewer than protons= $1.88\times 10^6$

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

= $\frac{Fewer\;electrons}{Total\;protons}$

The fraction of the protons would have no electrons

= $\frac{1.88\times 10^{6}}{1.00\times 10^{16}}$

$=1.88\times 10^{-10}$

Hence, the fraction of the protons would have no electrons $=1.88\times 10^{-10}$

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A person has a mass of 60 kg. What is the person’s weight in Newtons and in pounds?

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Assume it takes 10 J to stretch a spring 10 cm beyond its natural length. Find the work required (in Joules) to stretch the spri

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Answer:

W = 30 J

Explanation:

given,

Work done = 10 J

Stretch of spring, x = 0.1 m

We know,

dW = F .dx

we know, F = k x

$\int dW = \int_0^{0.1} k.x dx$

$W = \int_0^{0.1} k.x dx$

$W = k[\dfrac{x^2}{2}]_0^{0.1}$

$10 = k\dfrac{0.1^2}{2}$

k = 2000

now, calculating Work done by the spring when it stretched to 0.2 m from 0.1 m.

$W = \int_{0.1}^{0.2} 2000 x dx$

$W = 2000 [\dfrac{x^2}{2}]_{0.1}^{0.2} dx$

W = 1000 x 0.03

W = 30 J

Hence, work done is equal to 30 J.

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