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RSB [31]
3 years ago
10

A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from

the center of the wire. (in Nm2/C, keep 3 significant figures)
Physics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

E=35921.96N/C

Explanation:

From the question we are told that:

Radius r=0.321mm

Charge Density \mu=0.100

Distance d= 5.00 cm

Generally the equation for electric field is mathematically given by

E=\frac{mu}{2\pi E_0r}

E=\frac{0.100*10^{-6}}{2*3.142*8.86*10^{-12}*5*10^{-2}}

E=35921.96N/C

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Two power lines run parallel for a distance of 220 m and are separated by a distance of 40.0 cm. If the current in each of the t
daser333 [38]

Answer:

The magnitude of force is 1.86 N and the direction of force is towards the other wire.

Explanation:

Given:

Current flowing through each power line, I = 130 A

Distance between the two power lines, d = 40 cm = 0.4 m

Length of power lines, L = 220 m

The force exerted by the power lines on each other is given by the relation:

F = \frac{\mu_{0}LII }{2\pi d}

Substitute the suitable values in the above equation.

F = \frac{4\pi\times10^{-7}\times220\times130\times130 }{2\pi\times0.4}

F = 1.86 N

Since the direction of current flowing through the power lines are opposite to each other, so the force is attractive in nature. Hence, the direction of force experienced by the power lines on each other is towards the each other.

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3 years ago
Explain electrostatic force
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Answer:

Electrostatics is a branch of physics that studies electric charges at rest. Since classical physics, it has been known that some materials, such as amber, attract lightweight particles after rubbing. The Greek word for amber, or electron, was thus the source of the word 'electricity'.

4 0
3 years ago
A handwashing sink may be used for: A. Handwashing and Washing Dishes B. Handwashing and Washing Ready-to-Eat Foods C. Handwashi
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Read 2 more answers
A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica
-BARSIC- [3]

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

7 0
3 years ago
What is the definition of the coefficient of kinetic friction?
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The coefficient of kinetic friction<span> is the force between two objects when one object is moving, or if two objects are moving against each other</span>
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