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RSB [31]
3 years ago
10

A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from

the center of the wire. (in Nm2/C, keep 3 significant figures)
Physics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

E=35921.96N/C

Explanation:

From the question we are told that:

Radius r=0.321mm

Charge Density \mu=0.100

Distance d= 5.00 cm

Generally the equation for electric field is mathematically given by

E=\frac{mu}{2\pi E_0r}

E=\frac{0.100*10^{-6}}{2*3.142*8.86*10^{-12}*5*10^{-2}}

E=35921.96N/C

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kozerog [31]

Answer:

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Explanation:

The buoyant force is given by:

B=\rho_L V_{sub} g

where

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g is the acceleration due to gravity

In this problem, the liquid used in the two examples is the same, water, so \rho_L is the same; and g is the same as well. Therefore, the only difference between the two examples is V_{sub}.

For the piece of wood, we are told that the object is floating, so only a fraction of its total volume of 25.0 cm3 will be submerged: therefore the submerged volume will be less than 25.0 cm3. On the contrary, the problem tells us that the piece of iron is submerged, so the submerged volume in this case is 25.0 cm3. Therefore, the submerged volume for the iron is greater than for the piece of wood, so the buoyant force of the piece of iron is greater.

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3 years ago
How much is required to accelerate a 5kg mass at 20 m/s2
zhannawk [14.2K]

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A 25 kg box on a horizontal frictionless surface is moving to the right at a speed of 5.0 m s. The box hits and remains attached
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Answer:

Explanation:

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Answer:

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