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RSB [31]
3 years ago
10

A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from

the center of the wire. (in Nm2/C, keep 3 significant figures)
Physics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

E=35921.96N/C

Explanation:

From the question we are told that:

Radius r=0.321mm

Charge Density \mu=0.100

Distance d= 5.00 cm

Generally the equation for electric field is mathematically given by

E=\frac{mu}{2\pi E_0r}

E=\frac{0.100*10^{-6}}{2*3.142*8.86*10^{-12}*5*10^{-2}}

E=35921.96N/C

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Jared is reading an article about the heavy rains that have fallen recently in his town. But he can’t separate the facts from th
Crank
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</span>OPINIONS:
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<span>|         It’s that time of year again when the days are wet and cool.
The rainy season is the best season.
         Rain makes up part of Earth’s water cycle.
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            and precipitation occur in the form of rain.
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Snow this time of year makes people gloomy.
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6 0
3 years ago
Read 2 more answers
Change in speed over a given period of time is
Dvinal [7]

Explanation:

Acceleration is the change in speed over a given time period

8 0
3 years ago
Read 2 more answers
Constant speed is the same thing as average speed
larisa86 [58]
No, they have different definitions
4 0
2 years ago
Light bulb 1 operates with a filament temperature of 2700 K whereas light bulb 2 has a filament temperature of 2100 K. Both fila
Lemur [1.5K]

Answer:

0.3659

Explanation:

The power (p) is given as:

P = AeσT⁴

where,

A =Area

e = transmittivity

σ = Stefan-boltzmann constant

T = Temperature

since both the bulbs radiate same power

P₁ = P₂

Where, 1 denotes the bulb 1

2 denotes the bulb 2

thus,

A₁e₁σT₁⁴ = A₂e₂σT₂⁴

Now e₁=e₂

⇒A₁T₁⁴ = A₂T₂⁴

or

\frac{A_1}{A_2} =\frac{T_{2}^{4}}{T_{1}^{4}}

substituting the values in the above question we get

\frac{A_1}{A_2} =\frac{2100_{2}^{4}}{2700_{1}^{4}}

or

\frac{A_1}{A_2} }=0.3659

6 0
3 years ago
The current in a hair dryer measures 19 amps. The resistance of the hair dryer is 14 ohms. What is the voltage?
Masja [62]
Voltage  =  (current) x (resistance)

             =  (19 A)  x  (14 ohms)  =  266 volts .

Note:  Be careful using that thing ! 

It's dissipating

       I² R  =  (19 A)² x (14 ohms)  =  5,054 watts ! ! !

That's an awful lot of power for a blow-dryer ! 

The dryer is certainly not using very much of that power to run the fan. 
Most of it is being used to heat air.  5 kilowatts is more power than most
toasters or microwave ovens use, so please be careful with how much of
your hair or skin you expose to that hot-air blast.  You could probably cook
a meatloaf with it.

6 0
3 years ago
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