Answer:
Fc = 1579 [N]; ac = 15790.9 [m/s^2]
Explanation:
To solve this problem we must use the following formula that relates the centripetal force to the speed of rotation and the radius of rotation, respectively.
a)
where:
Fc = centripetal force [N]
m = mass [kg]
v = tangential velocity [m/s]
r = radius [m]
We have to give a mass to the stone in order to solve the problem, for this case we will say that the mass is equal to 100 [g].
The tangential velocity is equal to the product of the angular velocity (rotational) by the turning radius
v = w * r
But we need to convert the angular velocity units of revolutions per second to radians per second
v = 25.13*25 = 628.31[m/s]
Now replacing in the first equation:
![F_{c}=0.1*\frac{628.31^{2} }{25} \\F_{c}= 1579 [N]](https://tex.z-dn.net/?f=F_%7Bc%7D%3D0.1%2A%5Cfrac%7B628.31%5E%7B2%7D%20%7D%7B25%7D%20%5C%5CF_%7Bc%7D%3D%201579%20%5BN%5D)
b)
The second part will be only:
![a_{c}=\frac{v^{2} }{r} \\a_{c}=\frac{628.31^{2} }{25} \\a_{c}=15790.93[m/s^{2} ]](https://tex.z-dn.net/?f=a_%7Bc%7D%3D%5Cfrac%7Bv%5E%7B2%7D%20%7D%7Br%7D%20%5C%5Ca_%7Bc%7D%3D%5Cfrac%7B628.31%5E%7B2%7D%20%7D%7B25%7D%20%5C%5Ca_%7Bc%7D%3D15790.93%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
C
Explanation:
The speed of a molecule is directly related to its kinetic energy, which is directly related to the temperature. As the temperature increases, so does a molecule's speed. Of the options provided, only option C has a higher speed than 500m/s.
A large male cougar living in the Cascade Mountains kills a deer or elk every 9 to 12 days, eating up to 20 pounds at a time and burying the rest for later.Except for females with young, cougars are lone hunters that wander between places frequented by their prey, covering as much as 15 miles in a single night.Cougars rely on short bursts of speed to ambush their prey. A cougar may stalk an animal for an hour or more
hope this helps in any way ! :)
Answer:
1) Q ’= 8 Q
, 2) q ’= 16 q
, 3) r ’= ¾ r
Explanation:
For this exercise we will use Coulomb's law
F = k q Q / r²
It asks us to calculate the change of any of the parameters so that the force is always F
Original values
q, Q, r
Scenario 1
q ’= 2q
r ’= 4r
F = k q ’Q’ / r’²
we substitute
F = k 2q Q ’/ (4r)²
F = k 2q Q '/ 16r²
we substitute the value of F
k q Q / r² = k q Q '/ 8r²
Q ’= 8 Q
Scenario 2
Q ’= Q
r ’= 4r
we substitute
F = k q ’Q / 16r²
k q Q / r² = k q’ Q / 16 r²
q ’= 16 q
Scenario 3
q ’= 3/2 q
Q ’= ⅜ Q
we substitute
k q Q r² = k (3/2 q) (⅜ Q) / r’²
r’² = 9/16 r²
r ’= ¾ r
Answer:
60 kWh
Explanation:
The computation of the annual energy consumption in KW-h is shown below:
As we know that
1 kw = 1000 w
So, for 1400 W it would be
= 1,400 ÷ 1,000
= 1.4 kW
Now the number of hours it used in a year
= 7 minutes × 365 days ÷ 60 minutes
= 42.58333 hours
So in one year it used
= 1.4 kW × 42.58333
= 59.61 kWh
= 60 kWh
