Answer:
Explanation:
Electrical potential energy will be converted into kinetic energy .
Electrical potential energy when distance was 15 m .
E₁ = 9 x 10⁹ x - q² /d where q is magnitude of charge on electron or positron
E₁ = 9 x 10⁹ x - ( 1.6 x 10⁻¹⁹ )² /15
= - 1.536 x 10⁻²⁹ J .
Electrical potential energy when distance was 2 m .
E₁ =9 x 10⁹ x - q² /d where q is magnitude of charge on electron or positron
E₁ = 9 x 10⁹ x - ( 1.6 x 10⁻¹⁹ )² /2
= -11.52 x 10⁻²⁹ J .
Decrease in energy = (11.52 - 1.536 ) x 10⁻²⁹
= 9.984 x 10⁻²⁹ J .
This energy will be converted into kinetic energy and they will be distributed equally in each .
Energy of each = 9.984 x 10⁻²⁹ /2
= 4.992 x 10⁻²⁹ J .
1/2 m v² = 4.992 x 10⁻²⁹ , m is mass of electron
.5 x 9.1 x 10⁻³¹ v² = 4.992 x 10⁻²⁹
v² = 109.71
v = 10.47 m/s .
