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serious [3.7K]
3 years ago
14

A uniform disk of unknown mass M and radius R = 10 cm is free to rotate about its axis. A light cord is wrapped around the rim o

n the disk and then tied to a small can of mass m = 50 gm. The cord does not slip as it unwinds on the disk. When released the can moves down with acceleration 3.27 m/s2. Take g = 9.81 m/s2. What is the angular acceleration of the disk?
Physics
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

32.7\ rad/sec^2

Explanation:

We have given the acceleration of the cord is 3.27 m/sec^2 and acceleration due to gravity is 9.81 m/sec^2 there is a relation between the angular acceleration and the linear acceleration that is

Linear acceleration = angular acceleration × radius

We have given radius R = 10 cm =0.1 m

So \alpha = \frac{a}{R}=\frac{3.27}{0.1}=32.7\ rad/sec^2 here α is angular acceleration a is linear acceleration and R is radius

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