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lisabon 2012 [21]
3 years ago
7

Three pucks A, B, and C are shown sliding across ice at the noted speeds. Air and ice friction forces

Physics
1 answer:
likoan [24]3 years ago
3 0

Answer:

c=6 m/s

Explanation:

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What is the area of space around a magnet called?
erma4kov [3.2K]

Answer:

These acts of attraction and repulsion are called “magnetism”, and the magnetic space around a magnet is called the “magnetic field”

Explanation:

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3 years ago
The magnetic field lines due to a straight, current-carrying wire are __________. The magnetic field lines due to a straight, cu
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The magnetic field lines due to a straight, current-carrying wire are circular.

<u>Explanation:</u>

The concepts of Electromagnetism brought a new revolution to the science world. The idea is the source of many new modes of power and machines that reduces the manual work. Motors are the best example of machines that run on the concepts of electromagnetism. So the concept is that a current-carrying conductor induces a magnetic field in its nearby premise.

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3 years ago
Calcium chloride is used to make pickles. The calcium atom transfers electrons to chlorine atoms, leading to the formation of ch
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Calcium chloride contains ionic bonds.

Pennies contain metallic bonds.

Hydrochloric acid contains covalent bonds.



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3 0
3 years ago
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Water in a tank which is positioned 5 feet above the ground is _____ potential energy? (answers would be like thermal, electric,
LUCKY_DIMON [66]

Answer:

Mechanical

Explanation:

The tank is at rest. And energy of any substance at rest is known as potential energy.

Now, in forms of energy, potential energy is a type of mechanical energy.

Thus, the correct option is mechanical Energy.

8 0
2 years ago
Determine the image distance and image height for a 5.00 cm tall object placed 30.0 cm from a double convex lens with a focal le
vlabodo [156]

Answer:

The image distance is 30 cm

image height = - 5 cm

Explanation:

The formula for calculating the image distance is expressed as

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

From the information given,

u = 30

f = 15

By substituting these values into the formula,

1/15 = 1/30 + 1/v

1/v = 1/15 - 1/30 = (2 - 1)/30 = 1/30

Taking the reciprocal of both sides,

v = 30

The image distance is 30 cm

magnification = image height/object height = - v/u

Given that object height = 5 cm, then

image height/5 = - 30/30 = - 1

image height = - 5 * 1

image height = - 5 cm

8 0
1 year ago
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