Here,
Height (S) = 2m
Gravity on mars (g) = 3.7m/s^2
Initial velocity (u) = 0 m/s^2
By the one of the formula of the motion,
S = ut + 1/2at^2
2 = 0 * t + 1/2*3.7*t^2
2 = 1.85t^2
t^2 = 2/1.85 = 1.081
t =1.03s
So, it will take 1.03s long..
Answer:
The new force is 1/4 of the previous force.
Explanation:
Given
---- 
--- 
Required
Determine the new force
Let the two particles be q1 and q2.
The initial force F1 is:
--- Coulomb's law
Substitute 2 for r1
The new force (F2) is
Substitute 4 for r2
Substitute
The new force is 1/4 of the previous force.
The force constant is 2.145 N/m.
<h3>What is spring constant?</h3>
- The spring constant is the force required to stretch or compress a spring divided by the distance traveled by the spring. It is used to determine whether a spring is stable or unstable.
- K is the proportionality constant, also known as the 'spring constant.' Hooke's law (F = -kx) specifies stiffness and strength via the k variable. The greater the value of k, the greater the force required to stretch an object to a given length.
Using the relation;
T = 2π√m/k
T = time period = 0.45 s
m = mass of object in kilograms = 0.011kg
k = spring constant
To find k based on the formula,
k = 4 × (3.142)^2 × 0.011 / (0.45 )^2
k = 2.145 N/m
Therefore the force constant is 2.145 N/m.
To learn more about force refer to :
brainly.com/question/12785175
#SPJ4
a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how
long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175
s this is the time to fall from the top; it would take the same time to travel
upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175
= 0.35s
b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice
to solve this problem the time it takes to fall the final 0.13 m is: time it
takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to
fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it
takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m
is then twice this, or 0.08s
Answer: William Thomson, better known as Lord Kelvin
