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4 years ago

Ek=8J m=100g V=?How much is V going to be?Explain step by step, please

Physics

1 answer:

Darya [45]4 years ago

5 0

Answer:

Explanation:

If Ek is the kinetic energy and m is the mass and v is the velocity then v can be calculated as follows

Ek= 1/2 ×( m × v² )

2Ek= mv²

2Ek/m = v²

v =√(2Ek/m)

m = 0.1 kg

v= √(2x8/0.1)= 12.65 m/s

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4 years ago

A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/

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Answer:

At $t = (70 / 3) \; {\rm s}$ (approximately $23.3 \; {\rm s}$ .)

Explanation:

Note that the acceleration of the car between $t = 0\; {\rm s}$ and $t = 20\; {\rm s}$ ( $\Delta t = 20\; {\rm s}$ ) is constant. Initial velocity of the car was $v_{0} = 0\; {\rm m\cdot s^{-1}}$ , whereas $v_{1} = 35\; {\rm m\cdot s^{-1}}$ at $t = 20\; {\rm s}\!$ . Hence, at $t = 20\; {\rm s}\!\!$ , this car would have travelled a distance of:

$\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}$ .

At $t = 20\; {\rm s}$ , the truck would have travelled a distance of $x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}$ .

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Hence, the car would catch up with the truck at $t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}$ .

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4 years ago

Ek=8J m=100g V=?How much is V going to be?Explain step by step, please​

Ek=8J m=100g V=?How much is V going to be?Explain step by step, please