Answer:
new atmospheric pressure is 0.9838 ×
Pa
Explanation:
given data
height = 21.6 mm = 0.0216 m
Normal atmospheric pressure = 1.013 ✕ 10^5 Pa
density of mercury = 13.6 g/cm³
to find out
atmospheric pressure
solution
we find first height of mercury when normal pressure that is
pressure p = ρ×g×h
put here value
1.013 ×
= 13.6 × 10³ × 9.81 × h
h = 0.759 m
so change in height Δh = 0.759 - 0.0216
new height H = 0.7374 m
so new pressure = ρ×g×H
put here value
new pressure = 13.6 × 10³ × 9.81 × 0.7374
atmospheric pressure = 98380.9584
so new atmospheric pressure is 0.9838 ×
Pa
Answer:
The equivalent stiffness of the string is 8.93 N/m.
Explanation:
Given that,
Spring stiffness is
![k_{1}=20\ N/m](https://tex.z-dn.net/?f=k_%7B1%7D%3D20%5C%20N%2Fm)
![k_{2}=30\ N/m](https://tex.z-dn.net/?f=k_%7B2%7D%3D30%5C%20N%2Fm)
![k_{3}=15\ N/m](https://tex.z-dn.net/?f=k_%7B3%7D%3D15%5C%20N%2Fm)
![k_{4}=20\ N/m](https://tex.z-dn.net/?f=k_%7B4%7D%3D20%5C%20N%2Fm)
![k_{5}=35\ N/m](https://tex.z-dn.net/?f=k_%7B5%7D%3D35%5C%20N%2Fm)
According to figure,
and
is in series
We need to calculate the equivalent
Using formula for series
![\dfrac{1}{k}=\dfrac{1}{k_{2}}+\dfrac{1}{k_{3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bk%7D%3D%5Cdfrac%7B1%7D%7Bk_%7B2%7D%7D%2B%5Cdfrac%7B1%7D%7Bk_%7B3%7D%7D)
![k=\dfrac{k_{2}k_{3}}{k_{2}+k_{3}}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7Bk_%7B2%7Dk_%7B3%7D%7D%7Bk_%7B2%7D%2Bk_%7B3%7D%7D)
Put the value into the formula
![k=\dfrac{30\times15}{30+15}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7B30%5Ctimes15%7D%7B30%2B15%7D)
![k=10\ N/m](https://tex.z-dn.net/?f=k%3D10%5C%20N%2Fm)
k and
is in parallel
We need to calculate the k'
Using formula for parallel
![k'=k+k_{4}](https://tex.z-dn.net/?f=k%27%3Dk%2Bk_%7B4%7D)
Put the value into the formula
![k'=10+20](https://tex.z-dn.net/?f=k%27%3D10%2B20)
![k'=30\ N/m](https://tex.z-dn.net/?f=k%27%3D30%5C%20N%2Fm)
,k' and
is in series
We need to calculate the equivalent stiffness of the spring
Using formula for series
![k_{eq}=\dfrac{1}{k_{1}}+\dfrac{1}{k'}+\dfrac{1}{k_{5}}](https://tex.z-dn.net/?f=k_%7Beq%7D%3D%5Cdfrac%7B1%7D%7Bk_%7B1%7D%7D%2B%5Cdfrac%7B1%7D%7Bk%27%7D%2B%5Cdfrac%7B1%7D%7Bk_%7B5%7D%7D)
Put the value into the formula
![k_{eq}=\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{35}](https://tex.z-dn.net/?f=k_%7Beq%7D%3D%5Cdfrac%7B1%7D%7B20%7D%2B%5Cdfrac%7B1%7D%7B30%7D%2B%5Cdfrac%7B1%7D%7B35%7D)
![k_{eq}=8.93\ N/m](https://tex.z-dn.net/?f=k_%7Beq%7D%3D8.93%5C%20N%2Fm)
Hence, The equivalent stiffness of the string is 8.93 N/m.
The power of is series combination is Vn^2 times that of a parallel combination.
For series combination :
Req = R + R + R + ............... n times = nR
I = Δv/nr
Power = (Δv/nr)^2 × nr = Δv^2/nr
For parallel combination
1/req = 1/R + 1/R + 1/R +................(n times) = n/R
Req = R/n
Power = Δv/(R/n) = nΔv^2/R
Ratio = Δv^2/nr/n·Δv^2/R = 1/n^2
Hence, power of is series combination is Vn^2 times that of a parallel.
Learn more about parallel combination here:
brainly.com/question/12400458
#SPJ4
<span>The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the "Radio waves"
So, option B is your answer
Hope this helps!
</span>