Answer:
We are given:
m = 50g OR 0.05 kg
v = 1000 m/s
Force applied by the gunner in a second = 180 N
<u>Momentum(p) of the bullet:</u>
p = mv
p = 0.05 * 1000
p = 50 kg m/s
<u>Finding the recoil force:</u>
The units kg m/s are also known as 'N' (newtons)
So, we can say that the force exerted on every bullet is 50 N
According to the law of conservation of momentum, every bullet fired applies a force of 50N towards the gunner
Hence, we can say that the recoil force of every bullet is 50N
<u>Finding the number of bullets fired in a minute:</u>
We are given that the gunner applied an average force of 180N on the gun
we know that that can also be written as 180 kg m/s. Notice the 's' in the units of the momentum, it tells us that this force is applied every second
So, to find the amount of force applied in a minute, we can multiply it by 60
Force applied by the gunner in a minute = (60 * 180) = 10800 N
Let n be the number of bullets fired in a minute
We can say that the force applied by the gunner is equal to the force applied by a bullet times the number of bullets fired
F(gunner) = n * F(bullet)
10800 = n * 50
n = 10800/50
n = 216 bullets / minute
The gunner shoots 216 bullets in a minute
