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laila [671]
3 years ago
15

Jason has 5 carrots, he gives 2 to a friend. How many carrots does he have left?

Mathematics
2 answers:
Mazyrski [523]3 years ago
8 0

Answer:

Step-by-step explanation:

5-2 which is the question and the answer is 3 carrots left

MariettaO [177]3 years ago
7 0

Answer:3

Step-by-step explanation:

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Complete the following statement.
solong [7]

Answer:

Hello dude

- 1 \frac{21}{24}  + 1 \frac{22}{24}  =  +  \frac{1}{24}

so it's positive

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ツ

7 0
2 years ago
Need help with question 9
Lorico [155]

Hey!

----------------------------------------------------------------

Solution:

I would assume that the iron intake is combined between breakfast and lunch. So 8.25mg is too meals worth of iron. So all we have to do is subtract.

15 - 8.25 = 6.75

----------------------------------------------------------------

Answer:

6.75mg are still needed for his daily intake.

----------------------------------------------------------------

Hope This Helped! Good Luck!

8 0
2 years ago
What is two solutions for x>6
Daniel [21]

7>6

8>6

9>6

etc.

Possible values for x:

x=7

x=8

x=9

etc.

4 0
3 years ago
Please solve thank you​
Irina-Kira [14]

Answer: probably A

Step-by-step explanation:

7 0
2 years ago
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
2 years ago
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