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dexar [7]
3 years ago
8

How do you think weather can increase the demand for electricity?

Physics
1 answer:
Deffense [45]3 years ago
5 0

Answer:

Extreme temperatures can increase demand for heating and cooling, and the resulting increases in electricity demand can push up fuel and electricity prices.

Explanation:

You might be interested in
The moon Phobos orbits Mars
podryga [215]

Explanation:

For a circular orbit v= \sqrt{\frac{G.m}{r} } with G = 6.6742 × 10^{-11}

Given m = 6.42 x 10^23 kg and  r=9.38 x 10^6 m

=> v = 2137.3 m/s

I hope this is the correct way to solve

3 0
3 years ago
Kinetic energy depends on the height of an object above the ground?
s344n2d4d5 [400]
Annnnd? Ummmmmmmmmmmmmmm
5 0
3 years ago
Snorkelers breathe through tubes that extend above the surface of the water. In prin- ciple, a snorkeler could go deeper with a
Yanka [14]

Answer:

h = 1.02 m

Explanation:

This is a fluid mechanics exercise, where the pressure is given by

       P = P_{atm} + ρ g h

The gauge pressure is

      P - P_{atm}  = ρ g h

In this case the upper part of the tube we have the atmospheric pressure. and the diver can exert a pressure 10 KPa below the outside pressure, this must be the gauge pressure

     P_{m} =    P - P_{atm}

     P_{m} = ρ g h

     h =P_{m} / ρ g

calculate

     h = 10 103 / (1000 9.8)

     h = 1.02 m

This is the depth at which man can breathe

8 0
3 years ago
Which action will decrease the gravitational force between two objects?
WITCHER [35]

Answer:

It’s D

Explanation:

6 0
3 years ago
A 2,537-kg truck moving at 14 m/s strikes a car waiting at a traffic light, hooking bumpers. The two continue to move together a
slavikrds [6]

Answer:

1902.75 kg

Explanation:

From Law of conservation of momentum,

m₁u₁ + m₂u₂ = V (m₁ + m₂).................... Equation 1

make m₂ the subject of the equation,

m₂ = (m₁V - m₁u₁)/(u₂-V)..................... Equation 2

Where m₁ = mass of the truck, m₂ = mass of the car, u₁ initial velocity of the truck, u₂ = initial velocity of the car V = common velocity

Given: m₁ = 2537 kg, u₁ = 14, V= 8 m/s, u₂ = 0 m/s ( as the car was at rest waiting at a traffic light)

Substituting into equation 2.

m₂ =[2537(8) - 2537(14)]/(0-8)

m₂ = (20296-35518)/-8

m₂ = -15222/-8

m₂ = 1902.75 kg.

Thus the mass of the car = 1902.75 kg

5 0
3 years ago
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