<span>F-number is 2.21
The f-number is defined as the ratio of the focal length to the diameter of the entrance pupil. So the equation is
N = f/D
where
N = f-number
f = focal length
D = entrance pupil
With the telescope, the entrance pupil will be assumed to be equal to the lens diameter. So substituting the known values into the equation.
N = 1.325 m / 0.0600 m
N = 2.208333333
Rounding to 3 significant figures gives a F-number of 2.21</span>
Answer:
18.3 m , 25.4°
Explanation:
d1 = 6 m, θ1 = 40°
d2 = 8 m, θ2 = 30°
d3 = 5 m, θ3 = 0°
Write the displacements in the vector form
The total displacement is given by
magnitude of resultant displacement is given by
d = 18.3 m
Let θ be the angle of resultant displacement with + x axis
θ = 25.4°
Need a picture of the problem
The SI unit of mass is the kilogram, and
the SI unit of force is the Newton.
