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Andre45 [30]
3 years ago
11

a student weighs 1200N they are standing in an elevator that is moving downwards at a constant speed of

Physics
2 answers:
Anettt [7]3 years ago
8 0

Explanation:

use this R= m(g-a), where R = reaction = weight, m= mass, a= acceleration and g= acceleration due to gravity

baherus [9]3 years ago
6 0

Answer:

<em>Elevator That Is Moving Downwards At A Constant Speed Of 4.9 M/S. What Is The Magnitude Of The Net Force Acing On The Student?</em>

<em>This problem has been solved!</em>

<em>This problem has been solved!See the answer</em>

<em>This problem has been solved!See the answerA student weighs 1200N. They are standing in an elevator that is moving downwards at a constant speed of </em><em>4.9 m/s. What is the magnitude of the net force acing on the student?</em>

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Can someone help me?!!!!!
babunello [35]

Answer:

56 m/s

Explanation:

The time we are considering is

t = 15 s

The vertical velocity of the projectile is given by

v_y(t) = v_{0y}-gt

where

v_{0y}=100 m/s is the initial vertical velocity

g=9.8 m/s^2 is the acceleration due to gravity

Substituting t=15 s, we find the vertical velocity of the projectile at that time:

v_y = 100 m/s - (9.8 m/s^2)(15 s)=-47 m/s

where the negative sign means the direction is now downward.

The horizontal velocity does not change since there are no forces acting along that direction, so it remains constant:

v_x = 30 m/s

So, the magnitude of the velocity at the moment of impact is

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3 0
4 years ago
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