Answer:
11.3 m/s
Explanation:
KE₁ = KE₂
½m₁v₁² = ½m₂v₂²
½ (2 kg) v² = ½ (4 kg) (8 m/s)²
v ≈ 11.3 m/s
Complete Question
A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is
Compute U if the bulb remains on for 5h
Answer:
The value is
Explanation:
From the question we are told that
The power rating of the bulb is
The resistance is
The voltage is
The energy expanded is
The voltage
The frequency is
The time considered is
Generally power is mathematically represented as
=>
=>
So
=>
=>
=>
=>
=>
=>
The answer is 18000 J
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