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denpristay [2]
3 years ago
11

chanice drives her scooter 7 km north she stops for lunch and then drives 5 km east what distance did she cover. what was her di

splacment?
Physics
1 answer:
liberstina [14]3 years ago
3 0
Use pythagorean's theorem for this, with 7 as a and 5 as b. pythagorean's theorem says that a^2 + b^2 = c^2, so 7^2 * 5^2 = c^2. this gives you 49 + 25 = c^2, so 74 = c^2. c = sqrt 74, which is approximately 8.60 km
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When measurements are close to their true values, they are said to be
katovenus [111]

Answer:

When measurements are close to true

value they are called to be accurate

Explanation:

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3 years ago
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A 1,500 kg car’s speed changes from 30 m/s to 15 m/s after the brakes are applied. Calculate the work done onto the car from the
HACTEHA [7]

The work done onto the car is 506,250 J

The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.

From the parameters given:

  • The mass of the car = 1500 kg
  • The initial speed = 30 m/s
  • The final speed = 15 m/s

The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)

\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}

\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}

\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}

= 506,250 J

Therefore, we can conclude that the work done on the car is 506,250 J

Learn more about work done here:

brainly.com/question/18762601

7 0
3 years ago
in the 1950s an experimental train that had a mass of 33200kg was powered across a level track by a jet that produced a thrust o
Mashcka [7]

248482000  force*dist=work

4 0
3 years ago
What is the average velocity in m/y of a tectonic plate that has traveled 9000 km to the south in 60 million years
alexandr402 [8]

9,000,000 ÷ 60,000,000 = 0.15m/y

5 0
3 years ago
consider a charge of -15.0 mCmoving to the right a 2.00x10^6 m/s in a mganetic field of .0300 T pointing upwards. What is the ma
77julia77 [94]

Answer:

a = 1.13×10^-8 m/s²

Explanation:

f = ma = qvb \\ a =  \frac{qvb}{m}

q = 15×10^-3 C

v = 2×10^6 m/s

B = 0.03 T

m = 8.00 x10^10 kg

a = 900/8 x10^10

a = 1.13×10^-8 m/s²

5 0
3 years ago
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