To solve this, we use the Wien's Displacement Law as shown in the attached picture. First, convert the temperature to Kelvin.
C to F:
C = (F - 32)*5/9
C = (325 - 32)*5/9 = 162.78 °C
C to K:
K = C + 273
K = 162.78 + 273 = 435.78 K
λmax = 2898/435.78 =
<em>6</em><em>.65 μm</em>
The strength of the friction doesn't matter. Neither does the distance or the time the asteroid takes to stop. All that matters is that the asteroid has
1/2 (mass) (speed squared)
of kinetic energy when it lands, and zero when it stops.
So
1/2 (mass) (original speed squared)
is the energy it loses to friction in order to come to rest.
Answer:
Radius=15.773 m
Explanation:
Given data
v=29.5 km/h=8.2 m/s
μs=0.435
To find
Radius R
Solution
The acceleration is a centripetal acceleration which is experienced by the bicycle given by
This acceleration is only due to static force which given as
The maximum value of the static force is given as
where
FN is normal force equal to mass*gravity
Therefore when the car is on the verge of sliding
Therefore the minimum radius should be found by the bicycle move without sliding
So
Answer:
a) g.p.e.=mass × gravitational field strength × height
b) Eᵖ= 50 × 9.8 × 20
9800 (J)
