To solve this problem we must resort to the Work Theorem, internal energy and Heat transfer. Summarized in the first law of thermodynamics.

Where,
Q = Heat
U = Internal Energy
By reference system and nomenclature we know that the work done ON the system is taken negative and the heat extracted is also considered negative, therefore
Work is done ON the system
Heat is extracted FROM the system
Therefore the value of the Work done on the system is -158.0J
The correct option will be
D. Time, initial velocity and final velocity
The Formula can be written as,
Acceleration=Final velocity-Initial Velocity/Time
Answer:
d. None of the above.
Explanation:
In a parabolic motion, you have that in the complete trajectory the component velocity is constant and the vertical component changes in time. Then, the total velocity vector is not zero.
In the complete trajectory the gravitational acceleration is always present. Then, the grasshopper's acceleration vector is not zero.
At the top of the arc the grasshopper is not at equilibrium because the gravitational force is constantly acting on the grasshopper.
Then, the correct answer is:
d. None of the above.
Answer:
<h2>
HIGHER & MORE OR LARGER OR MORE </h2>
HENCE, THE ANSWER IS A. :)
Explanation:
<em><u>#</u></em><em><u>CARRYONLEARNING</u></em>
<em><u>BRAINLIEST</u></em><em><u> </u></em><em><u> </u></em><em><u>PLEASE</u></em><em><u> </u></em><em><u>I </u></em><em><u>REALLY </u></em><em><u>NEED</u></em><em><u> </u></em><em><u>IT</u></em>