Using the scale model of the Sun given;
- The diameter of the Milky Way = 4.28 × 10¹¹ m
- The diameter of the Earth = 5.44 × 10⁻³ m
<h3>What is the diameter of the Milky Way?</h3>
The diameter of the Milky Way is about 1 × 10¹⁸ km.
The diameter of the Sun is about 1.4 × 10⁶ km
The diameter of the Earth is about 1.27 × 10⁴ km.
Using the scale model of the Sun given, the diameter of the Milky Way = (1 × 10¹⁸ km/1.4 × 10⁶ km) × 0.6 m
The diameter of the Milky Way = 4.28 × 10¹¹ m
Using the scale model of the Sun given, the diameter of the Milky Way = (1.27 × 10⁴ km/1.4 × 10⁶ km) × 0.6 m
The diameter of the Earth = 5.44 × 10⁻³ m
In conclusion, the diameter of the Milky Way is far bigger than the Sun while the diameter of the Sun is about 5400 times bigger than the Earth.
Learn more about the Milky Way, Sun, and Earth at: brainly.com/question/1995133
#SPJ1
Answer;
-Mass
Explanation;
-An intensive property is a physical quantity whose value does not depend on the amount of the substance for which it is measured. For example, boiling point, density, color, melting point, Odor, temperature, etc.
-Extensive properties on the other hand, do depend on the amount of matter that is present. An extensive property is considered additive for subsystems. Examples of extensive properties include: volume, mass, size, weight. length, etc.
The cart is moving by simple harmonic motion, and its position at time t is described by

where
A is the amplitude of the oscillation

is the angular frequency
The amplitude of the oscillation corresponds to the maximum displacement of the spring, which corresponds to the initial position where the spring was released:
A=0.250 m
The period of the motion is T=5.67 s, and the angular frequency is related to the period by

Therefore now we can calculate the position of the system at the time t=29.6 s: