Question

Write a balanced equation for the neutralization of potassium hydroxide by phosphoric acid . Use the smallest possible integer coefficients.

Answer 1

Answer:

Using the smallest coefficient the chemical equation is written as

3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)

Explanation:

Neutralization reaction is a reaction in which acid and base reacts quantitatively to form salt and water.

Base = potassium hydroxide

acid = phosphoric acid.

KOH =potassium hydroxide

H3PO4 = Phosphoric acid

KOH(aq) + H3PO4(aq) → K3PO4(aq) + H2O(aq)

The number of atoms on both side (reactant and product) of the equation are not equal so, we need to balance it.

3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)

The product are salt and water.

Salt = K3PO4

water = H2O

The equation is balanced on both sides .

The potassium atom is 3 on both sides , oxygen atom is 7 on both sides, hydrogen atom is 6 on both sides and phosphorus atom is 1 on both sides.