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stiks02 [169]
3 years ago
9

Write a balanced equation for the neutralization of potassium hydroxide by phosphoric acid . Use the smallest possible integer c

oefficients.
Chemistry
1 answer:
Mrrafil [7]3 years ago
5 0

Answer:

Using the smallest coefficient the chemical equation is written as

3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)

Explanation:

Neutralization reaction is a reaction in which acid and base reacts quantitatively to form salt and water.

Base = potassium hydroxide

acid = phosphoric acid.

KOH =potassium hydroxide

H3PO4 = Phosphoric acid

KOH(aq) + H3PO4(aq) → K3PO4(aq) + H2O(aq)

The number of atoms on both side (reactant and product) of the equation are not equal so, we need to balance it.

3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)

The product are salt and water.

Salt = K3PO4

water = H2O

The equation is balanced on both sides .

The potassium atom is 3 on both sides , oxygen atom is 7 on both sides, hydrogen atom is 6 on both sides and phosphorus atom is 1 on both sides.

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Two types of liquids, two types of gases, two types of solids.
snow_tiger [21]

Answer:

liquids: water and soda

gases: oxygen and carbon dioxide

solid: a chair and a notebook

3 0
3 years ago
Read 2 more answers
Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of
dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • HCl: 2 moles
  • NaCl: 2 moles
  • CO₂: 1 mole
  • H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

8 0
3 years ago
An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The
Nataly_w [17]

Answer:

67

Explanation:

5 0
3 years ago
Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0
Lena [83]

Answer:

6.096799125kg

Explanation:

According to the question, three different samples weighed using different types of balance had masses: 0.6160959 kg, 3.225 mg, and 5480.7 g.

Based on observation, the mass units in the three measurements are different but must be uniform in order to find the total mass. Hence, we need to convert to the standard unit (S.I unit of mass), which is kilograms (kg)

Since 1kg equals 1,000,000mg

Hence, 3.225mg will be 3.225/1000000

= 0.000003225kg

Also, 1kg equals 1000g

Hence, 5480.7g will be 5480.7/1000

= 5.4087kg

Hence, the total mass of the three samples (now in the same unit) are:

5.4807kg + 0.000003225kg + 0.6160959 kg

= 6.096799125kg

3 0
3 years ago
Aluminium sulfate hydrate al2(so4)3.xh2o contains 13.63% al by mass. calculate x, that is, the number of water molecules associa
Advocard [28]
MAl₂(SO₄)₃·xH₂O:
(mAl×2) + (mS×3) + (mO×12) + (mH₂O×x)
(27×2)+(32×3)+(16×12)+(x×18) = 342 + 18x [g]
mAl₂: 27×2 = 54 [g]

54g ---------- 13,63%
342+18x ---- 100%
0,1363(342+18x) = 54
46,6146 + 2,4534x = 54
2,4534x = 7,3854
x ≈ 3

>>> Al₂(SO₄)₃·3H₂O <<<<
:)
8 0
3 years ago
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