100 degree celcius and 0 degree Celsius
A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the
solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.
Answer:
<h2>6.14 cm³</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question we have
We have the final answer as
<h3>6.14 cm³</h3>
Hope this helps you
Answer:
The correct answer is 930 grams platelets.
Explanation:
The volume of blood given is 1.89 pints. Total number of gallons in 1.89 pints is,
= 1.89/8 = 0.236 gallon
1 gallon comprise = 3.785 L
So, 0.236 gallon comprise = 0.236 * 3.785 L = 0.89 L
As mentioned that 1 Liter of blood comprise 1.04 kilograms of platelets. Therefore, 0.89 L of blood will contain = 1.04 * 0.89 = 0.93 Kg platelets
1 Kg contain 1000 grams. So, number of platelets in grams will be,
= 1000 * 0.93 = 930 grams platelets.
3Mg + N₂ = Mg₃N₂
Mg₃N₂
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