3 years ago

I WILL MARK YOU BRAINLIEST!!!!

Mathematics

1 answer:

satela [25.4K]3 years ago

5 0

Answer:

0; one real roots

* the answer is C

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How do I solve this? (please help to find what goes in the boxes as well)

natta225 [31]

Answer:

First Box: Factor by difference of squares

Second Box: It has all perfect squares

Third Box: see my work

Step-by-step explanation:

We have the equation $4x^2=36$

Before we do anything, let us bring all of the terms to the left side

$4x^2-36=0$

Now that we have moved the terms to one side, it is clear that we have a difference of squares.

-Work-

$4x^2=36\\\\4x^2-36=0\\\\(2x+6)(2x-6)=0\\\\$

$2x+6=0\\\\2x=-6\\\\x=-3$

$2x-6=0\\\\2x=6\\\\x=3$

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