
<u>Step-by-step explanation:</u>
We have ,
,
We know that ![sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }](https://tex.z-dn.net/?f=sin%5Calpha%20%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7B%5Csqrt%5B2%5D%7B%28Perpendicualr%29%5E%7B2%7D%20%2B%20%28Base%29%5E%7B2%7D%29%7D%20%7D)
Substituting values of P & B , 
Now , 
⇒
×
×2
⇒ 
⇒
⇒
⇒
Answer:
Option (1)
Step-by-step explanation:
Given inequality is.
4x + 5 ≥ 13
We will further solve this inequality,
(4x + 5) - 5 ≥ 13 - 5
4x ≥ 8

x ≥ 2
Therefore, on a number line solution of x will be all values of x greater than equal to 2.
Which will be represented by and arrow starting with a solid point from x = 2 directing towards numbers greater than 2.
Option (1) will be the answer.
Answer:
480 mm³
Step-by-step explanation:
The volume (V) of a pyramid is
V =
area of base × height, hence
V =
× 96 × 15 = 32 × 15 = 480
Answer:
both each side of each triangle is equal
use alphabets to mark each edge of the triangles and prove congruency