Answer:
The answer to the question is;
The number of ATP molecules the cell synthesize for each molecule of pyruvate oxidized to carbon dioxide and water is 14 ATP molecules.
Explanation:
The chemical reaction for glycolysis is
Glucose + 2 NAD⁺ + 2 Pi + 2 ADP → 2 pyruvate + 2 NADH + 2 ATP + 2 H⁺ + 2 H₂O + heat
As seen above, each glucose molecule produces 2 pyruvate molecules and 2 ATP. Therefore, if the cell can produce 30 ATP per glucose molecule then, since 2 ATP are already produced directly by the glycolysis of glucose, the remaining 28 ATP re produced from the two pyruvate molecules
Therefore, the number of ATP molecules the cell can synthesize for each pyruvate oxidized to carbon dioxide and water is 28/2 or 14 ATP.
Answer:
1: The speculation that continents might have 'drifted' was first put forward by Abraham Ortelius in 1596. The concept was independently and more fully developed by Alfred Wegener in 1912, but his hypothesis was rejected by many for lack of any motive mechanism. 2: The most obvious evidence for continental drift is that the continents appear to fit together like pieces of a puzzle. But scientists were skeptical , and Wegener needed additional evidence to support his hypothesis. Glaciers covered large areas that are now parts of these continents.
61.8 % is the mass percentage of magnesium sulphate.
Explanation:
The mass percent of individual solute or ion in a compound is calculated by the formula:
Grams of solute ÷ grams of solute + solvent × 100
mass percent of magnesium is calculated as 1 mole of magnesium having 24.305 grams/mole will have weight of 24.305 grams and 1 mole of MgSO4 will have 120.366 grams
Putting the values in the equation:
24.305 ÷ 144.671 × 100
= 16.8% of magnesium is in the mixture
The mass percentage of SO4 is calculated as
= 96.06 ÷ 216.426 × 100
= 44.38 %
The mass percentage of the mixture MgSO4 is 44.38 + 16.8 = 61.8 %
Mass percentage is a representation of the concentration of element or elements in a compound.
Answer:- 
and 
Explanations:- In the first equation, the oxidation number of O is decreasing from 0 to -2 where as the oxidation number of H is increasing from 0 to +1. As the oxidation number is increasing for one element(H) and decreasing for other element(O), it is an oxidation-reduction reaction.
Second reaction is a double displacement reaction so there is no change to the oxidation numbers of the elements and hence it is not oxidation-reduction reaction.
In third reaction, the oxidation number of Al is increasing from 0 to +3 and the oxidation number of H is decreasing from +1 to 0. Here again there is an increase and decrease to the oxidation numbers of two elements, it is oxidation-reduction reaction.
fourth and fifth reactions are again double displacement reactions and so there is no change to oxidation numbers for any of the elements and they are not the oxidation-reduction reactions.
So, the only correct equations are and .
