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Svetach [21]
3 years ago
9

Question: Is a flame matter?

Physics
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

Depends on the point you want to make,if you are making the point a flame is not matter than you will put something like....

Flames are not matter because(a point that you have saying it isnt ).

If you are saying it is then put something like....  flames are matter because (a point you have that says it is.)

Explanation:

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Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

The incident index is n_i=\frac{4}{3} and the transmitted index is n_t= 1.

The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

6 0
3 years ago
Jill leaves home and rides a distance of 70 km. It took her 2.5 hours. What is her speed?
Paraphin [41]
The answer is ...
28 km per hour
5 0
3 years ago
10. Electrical Power: Why do our electronic devices get hot? We know
Vesna [10]

Answer:

Now, think on the electrons flowing through a conductor (we can think on the resistor as a simple conductor, like a piece of metal)

Inside the conductor, we have some "fixed" (they do not flow with the current) electrons, such that as the current flows in the conductor, the flowing electrons can interact with the fixed ones in the conductor. Then we can have collisions inside the conductor.

In those collisions, the flowing electrons leave energy in the conductor, and as we know, heat is a form of energy. Then when we have a lot of these collisions, the temperature of the conductor increases.

That is why electronic devices get hot.

Also, as the temperature of a conductor increases, the electrons inside of it start to move more, then the probability of an interaction with the flowing electrons increases.

3 0
3 years ago
What is meant by the following terms: a) beat; b) subdivision; c) meter; d) accents; e) syncopation; and f) tempo
suter [353]

Answer:

(a) <em>Beat</em>: A beat defines the movement and speed of a rhythm. It describes the flow of the rhythm of a piece of music. There are various concepts related to beat such as tempo, groove and meter.

(b) <em>Subdivision: </em>Subdivision typically means dividing a large entity into smaller entities. In music, rhythms can be broken down into sub-sequences. For example, starting with a whole note, the note can be divided into quarter notes which can further be subdivided into eight notes and so on.

(c) <em>Meter</em>: A meter describes the structure of a beat. It is sometimes represented as the time signature of a song. It defines how many individual beats there would if one were clapping their hands to the beat of a song.

(d) <em>Accents</em>: Accents refer to the stress or emphasis laid on a chord or musical note. They are a large measuring factor in the articulation of a musical piece.

(e) <em>Syncopation</em>: In music, syncopation describes an element of surprise. It occurs when rhythmic patterns fall on weak beats (or weak parts of the beat) rather than on strong beats. These kind of rhythms are usually easy to sing but difficult to transcribe.

(f) <em>Tempo</em>: The tempo of a beat in music is typically the speed of the beat - how fast the beats are being played or sung. It is often measured in beats per minute (BPM). This means that tempo is the number of beats played per minute.

6 0
3 years ago
Please help on this one?
ruslelena [56]

Answer:

A, 30V

Explanation:

First combine all resistors to an equivalent resistor. Since they are in series, the equivalent resistance is the sum of all resistor

Req = 20 + 40 + 60 = 120Ω

Using Ohm's law, find the current in the circuit

V = I * R

I = V / R

I = 60V / 120Ω

I = 0.5 A

Now the potential drop across the resistor R3 is the current times R3 resistance, therefore:

Vdrop = 0.5A * 60Ω = 30V

So the potential drop across resistor R3 is 30 V

3 0
3 years ago
Read 2 more answers
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