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3 years ago

9

Question: Is a flame matter?

1 answer:

Butoxors [25]3 years ago

5 0

Answer:

Depends on the point you want to make,if you are making the point a flame is not matter than you will put something like....

Flames are not matter because(a point that you have saying it isnt ).

If you are saying it is then put something like.... flames are matter because (a point you have that says it is.)

Explanation:

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Give the reason that antifreeze is added to a car radiator

Illusion [34]

As it's name suggests it is a liquid with a very low freezing point. When added to the water in your car's cooling system it keeps it from freezing in cold weather. If the water in your cooling system freezes the radiator and associated piping would crack.

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3 years ago

Read 2 more answers

As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly and at -4.1m/s^2 as it slows from 9.0

Tju [1.3M]

Hope this helps you.

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3 years ago

1 A steel ball of mass 5 kg is released from rest at a height of 3 m above the ground. It rolls down the frictionless section AB

KonstantinChe [14]

The speed of the ball when it reached the point B is 7.7 m/s. The angle of inclination of section BC is 11.54⁰.

<h3>What is frictional force?</h3>

The force between the two mating surfaces and having the relative motion is called the frictional force.

The speed of ball at point B is equal to the relation

v = √(2gh)

Substitute the values of height h = 3m and acceleration due to gravity g =9.8 m/s², we get the speed at B

v =√(2 x 9.8 x 3)

v =7.7 m/s

Thus the speed of ball when it reaches the point B is 7.7 m/s.

Given is the mass of steel ball is 5 kg and the frictional force is 10N.

The frictional force is equal to the product of coefficient of friction and the normal force on the steel ball \.

f = μN

f =μmg

Substitute the values into the equation, we get the coefficient of friction.

10 = μ x 5 x 9.8

μ = 0.2041

Angle of inclination for the section BC is

θ = tan⁻¹(0.2041) = 11.54⁰

Thus, the angle of inclination of section BC is 11.54⁰.

Learn more about frictional force.

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2 years ago

If a net horizontal force of 175 N is applied to a bike whose mass is 50 kg what acceleration is produced?

Crazy boy [7]

The acceleration of the bike is $3.5 m/s^2$

Explanation:

We can solve this problem by using Newton's second law of motion, which states that:

$F=ma$

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the bike in this problem, we have

F = 175 N is the net force

m = 50 kg is the mass

And solving for a, we find the acceleration:

$a=\frac{F}{m}=\frac{175}{50}=3.5 m/s^2$

Learn more about Newton's second law and acceleration:

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4 years ago

suppose all the grains in a sample of sand were exactly the same size. Could the sample still be a heterogeneous mixture?

DanielleElmas [232]

Depends on if the samples are different kinds of sand

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3 years ago