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Dmitry [639]
3 years ago
13

the train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time?

Physics
2 answers:
lord [1]3 years ago
7 0
So I believe that you have to use s=ut+1/2at2 so s=15 into 20+1/2 into 3 into 400 this is equal to 900m btw idk if it’s true perhaps you can check on snapsolve
Anvisha [2.4K]3 years ago
5 0
18meters per 20 seconds so
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Use the information from the graph to answer the question.
galina1969 [7]

The displacement of the object as determined from the velocity-time graph is 562.5 m.

<h3>What is a velocity-time graph?</h3>

A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.

The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.

The total area under the graph = area of triangle + area of rectangle

Area of triangle = b*h/2 =

Area of triangle = 25 * (35 - 10)/2 = 312.5 m

Area of rectangle = l * b

Area of rectangle = 10 * 25 = 250 m

Total area = (312.5 + 250) m

Total area = 562.5 m

Therefore, the displacement of the object is 562.5 m

In conclusion, the total area of a velocity-time graph gives the displacement.

Learn more about velocity-time graph at: brainly.com/question/28064297

#SPJ1

5 0
1 year ago
Hi, I need your help with this Physics exercise, I hope you can help me A pulse moving to the right along the x axis is represen
igomit [66]

Answer:

Velocity = 0.309 m/s

Along negative x axis

Explanation:

A pulse moving to the right along the x axis is represented by the wave function

y(x,t) = 2/ (x - 3t)² + 1

At t =0

y(x,0) = 2/ ((x - 3(0))² + 1)

        =2 / (x² + 1)

At t = 1

y(x,t) = 2/ ((x - 3(1))² + 1)

= 2 /(( x - 3)² + 1)

At t = 2

y(x,t) = 2/ ((x - 3(2))² + 1)

= 2 /(( x - 6)² + 1)

For the pulse with expression y(x,t) = 4.5e^{-(8.73x + 2.70t)}²

The Velocity is

V = 2.7 / 8.73

= 0.309 m/s

3 0
3 years ago
Which equation could not be used to determine straight line acceration?
uranmaximum [27]

Answer:

the answer for the question is the last option

5 0
3 years ago
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Blababa [14]
Ans is a male having the disease.
3 0
3 years ago
Read 2 more answers
Please!!! I need some help!!! I will give Brainliest To anyone who truly helps.
djyliett [7]

Answer:

Please INCLUDE a picture.

Explanation:

You did not include a picture, so there is no way to tell how the charges will interact with each other.

Please INCLUDE a picture.

5 0
3 years ago
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