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3 years ago

What is the acceleration of a car that travels in a straight line at a constant speed?

Physics

1 answer:

andre [41]3 years ago

4 0

Is a it’s depends what speed the car has

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Power windmills turn in response to the force of high-speed drag. For a sphere moving through a fluid, the resistive force, FR i

Crazy boy [7]

Answer:

The answer is 20727w

Explanation:

The formula is below;

P = d r^2 v^3 *efficiency

In the question, it is stated that the registration ignores efficiency so we are going to ignore efficiency in the equation and use it this way;

P = d r^2 * v^3

d =4.3, r = 1.59, v =n 12.4

Therefore, P = 4.3 X 1.59^2 X 12.4^3 = 20727W

3 0

3 years ago

Make the following conversion.

blsea [12.9K]

Answer: 56320

Explanation:

7 0

3 years ago

Read 2 more answers

A ruby laser delivers a 16.0-ns pulse of 4.20-MW average power. If the photons have a wavelength of 694.3 nm, how many are conta

stepan [7]

Answer:

The value is $n = 2.347 *10^{17} \ photons$

Explanation:

From the question we are told that

The amount of power delivered is $P = 4.20 \ M W = 4.20 *10^{6} \ W$

The time taken is $t = 16.0ns = 16.0 *10^{-9} \ s$

The wavelength is $\lambda = 694.3 \ nm = 694.3 *10^{-9} \ m$

Generally the energy delivered is mathematically represented as

$E = P * t = \frac{n * h * c }{\lambda }$

Where $h$ is the Planck's constant with value $h = 6.262 *10^{-34} \ J \cdot s$

c is the speed of light with value $c = 3.0*10^{8} \ m/s$

$4.20 *10^{6} * 16*10^{-9}= \frac{n * 6.626 *10^{-34} * 3.0*10^{8} }{694.3 *10^{-9}}$

=> $n = 2.347 *10^{17} \ photons$

4 0

3 years ago

The property of matter that resists changes in motion is called...

arlik [135]

Answer:

inertia

Explanation:

i hade the same question

4 0

3 years ago

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You are conducting an experiment inside a train car that may move along level rail tracks. A load is hung from the ceiling on a

Triss [41]

Here the weight is hung from the thread inside the ceiling of train

now the FBD of train is analysed

We can say

$Tcos\theta = mg$

$Tsin\theta = ma$

now by ratio of two equations we have

$a = gtan\theta$

this shows that train must be in accelerating condition due to which the thread is making an angle with the vertical

now we will have

2 The train is not an inertial frame of reference.

Since train is accelerating so it must be non inertial frame

5 The train may be moving at a constant speed in a circle.

Since its moving in circle so it is in accelerating condition

8 The train must be accelerating.

3 0

3 years ago