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saul85 [17]
3 years ago
7

Someone please help me and will give BRAILIEST!!!!

Physics
1 answer:
pishuonlain [190]3 years ago
4 0
Answer is C carbon....................
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True or False?
34kurt
That's true.
Newton's law of universal gravitation says that the gravitational
force between two objects is

                      F  =  G · M₁ · M₂ / D²  .

There's no note under the equation that says "only up to
this certain distance, and zero any farther than that".

The equation is true no matter how gigantic the distance
is between the objects.
4 0
2 years ago
Please help I’m so desperate I’m giving about all my points
alexira [117]

Answer:

1 and 5

Explanation:

potential energy is movement energy, and at 1 and 5 there is a lot of kinetic energy (built up energy) and not a lot of potential energy

7 0
2 years ago
You are lying on a beach, your eyes 20cm above the sand. Just as the Sun sets, fully disappearing over the horizon, you immediat
Naya [18.7K]

Answer:

The  time is  t =  8.78 \ s

Explanation:

From the question we are told that  

  The  initial height of the eye  is  h _1 =  20 \  cm =  0.2 \  m

  The  height of the eye when you jumped up is h_2  =  150 \  cm  =  1.5 \  m

 An illustration of this question is shown on the first uploaded image

Generally the radius of the earth is  R  =  6.38*10^{6} \  m

Now from the diagram first sun means first time you saw the sun and  the second sun means second time you saw the sun then

   H is the height increase when you quickly stood up which is mathematically evaluated as

        H  =  h_2 -h_1

        H  = 1.5 -  0.2

        H  = 1.3 \ m

Also \theta i the angular displacement between the first and second position and from geometry it is also the angle at  one of the sides of the right angle triangle

Applying Pythagoras theorem

     (R+H)^2  =  K^2  + R^2

=>   R^2 + H^2 + 2RH  =  K^2  + R^2

Now given that H is very small compared to R the we ignore H^2

So

     R^2 + 2RH  =  K^2  + R^2

=>    K  =  \sqrt{2RH}

=>     K  =  \sqrt{2 *  6.38*10^6 * 1.3 }

=>      K  = 4073 \  m

Now the \theta is mathematically evaluated using SOHCAHTOA as follows

      tan  \theta  =  \frac{K}{R}

      \theta  = tan^{-1}[ \frac{K}{R}]

=>   \theta  = tan^{-1}[ \frac{ 4073}{6.38*10^{6}}]

=>   \theta = 0.0366^o

Generally

  1 \revolution\  around \ the\ earth =  24 \ hours =  86400 \ seconds =  360 ^o

So  

    \frac{\theta}{360}  =  \frac{t}{86400}

=>  \frac{0.0366}{360} =  \frac{t}{86400}

=>  t =  8.78 \ s

6 0
3 years ago
A cube of side 6.50 cm is placed in a uniform field E = 7.50 × 10^3 N/C with edges parallel to the field lines (field enters the
Svetllana [295]

Answer:

a) \Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}, b) \Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}, c) \Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}

Explanation:

a) The net flux through the cube is:

\Phi_{net}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}+(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}

b) The flux through the right face is:

\Phi_{right}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}

c) The flux through the left face is:

\Phi_{left}=(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}

5 0
3 years ago
Read 2 more answers
100 meters toward the shore in 25 seconds
Rzqust [24]

Answer:

The speed of a turtle is 4m/s

Explanation:

speed = distance/time

distance = 100m

time = 25s

s = 100/25

= 4m/s

6 0
3 years ago
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