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Greeley [361]
3 years ago
7

How much energy in kilojoules is released when 23.4 g of ethanol vapor at 83.0 ∘C is cooled to -15.0 ∘C ?

Chemistry
1 answer:
slamgirl [31]3 years ago
5 0

Answer : The amount of in kilojoules released is, -5.53 kJ

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat released = ?

c = specific heat of ethanol = 2.41J/g^oC

m = mass of ethanol = 23.4 g

T_{final} = final temperature = -15.0^oC

T_{initial} = initial temperature = 83.0^oC

Now put all the given values in the above formula, we get:

q=23.4g\times 2.41J/g^oC\times (-15.0-83.0)^oC

q=-5526.612J=-5.53\times 10^3J=-5.53kJ

Therefore, the amount of in kilojoules released is, -5.53 kJ

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Considering the definition of molar mass, the moles of gas used are 10.625 moles.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Amount of moles used</h3>

Natural gas has a molar mass of 16.0 g/mole.

You started out the day with a tank containing 200.0 g of natural gas.  So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 200 grams are contained in how many moles?

amount of moles at the beginning=\frac{200 gramsx1 mole}{16 grams}

<u><em>amount of moles at the beginning= 12.5 moles</em></u>

At the end of the day, your tank contains 30.0 g of natural gas. So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 30 grams are contained in how many moles?

amount of moles at the end=\frac{30 gramsx1 mole}{16 grams}

<u><em>amount of moles at the end= 1.875 moles</em></u>

The number of moles used will be the difference between the number of moles used initially and the contents at the end of the day.

moles used= amount of moles at the beginning - amount of moles at the end

moles used= 12.5 moles - 1.875 moles

<u><em>moles used= 10.625 moles</em></u>

<u><em /></u>

Finally, the moles of gas used are 10.625 moles.

Learn more about molar mass:

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