How much energy in kilojoules is released when 23.4 g of ethanol vapor at 83.0 ∘C is cooled to -15.0 ∘C ?
1 answer:
Answer : The amount of in kilojoules released is, -5.53 kJ
Explanation :
Formula used :
where,
q = heat released = ?
c = specific heat of ethanol =
m = mass of ethanol = 23.4 g
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get:
Therefore, the amount of in kilojoules released is, -5.53 kJ
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Answer:
Explanation:
Given parameters:
Initial temperature T₁ = 25.2°C = 25.2 + 273 = 298.2K
Initial pressure = P₁ = 0.6atm
Final temperature = 72.4°C = 72.4 + 273 = 345.4K
Unknown:
Final pressure = ?
Solution:
To solve this problem, we use an adaption of the combined gas law where the volume gas is fixed. This simplification results into:
where P and T are temperatures, 1 and 2 are initial and final temperatures.
Input the parameters and solve;
P₂ = 0.7atm
Answer:
16.5 days
Explanation:
Given that:
Half life = 26.5 days
Where, k is rate constant
So,
The rate constant, k = 0.02616 days⁻¹
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
35.0 % is decomposed which means that 0.35 of is decomposed. So,
= 1 - 0.35 = 0.65
t = 7.8 min
<u>t = 16.5 days.</u>