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liubo4ka [24]
3 years ago
13

Which pair has identical electron configurations?

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
6 0

Identical electron configurations : K⁺ and Cl⁻

<h3>Further explanation  </h3>

In an atom, there are levels of energy in the shell and sub-shell  

This energy level is expressed in the form of electron configurations.  

Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

  • S²⁻ and CI

S²⁻ : [Ne] 3s²3p⁶

Cl : [Ne] 3s²3p⁵

  • K⁺ and CI⁻

K⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶

Cl⁻ : 1s² 2s² 2p⁶ 3s²3p⁶

  • S and Ar

S :[Ne] 3s²3p⁴

Ar : [Ne] 3s²3p⁶

  • Cl⁻ and K

Cl⁻ : 1s² 2s² 2p⁶ 3s²3p⁶

K : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹

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How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

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In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

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If .758 moles of gas occupy a volume of 80.6L, how many moles will occupy a volume of 270.9L?
egoroff_w [7]

Answer:

n₂ = 2.55 mol

Explanation:

Given data:

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Solution:

Formula:

V₁/n₁ = V₂/n₂

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n₁ = initial number of moles

V₂ = Final volume

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