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The answer is- is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.
Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.
Determine the molecular geometry of .
- Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
- According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
- Now, calculate the total number of valence electrons in
.
Valence electrons of S = 6
Valence electrons of F = 7
Thus, the valence electrons in are-
- The Lewis structure of
- In the structure, the number of atoms bonded to central atom (S) = 6.
- Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
- Electronic geometry in case of 6 bond pairs is octahedral.
- Molecular geometry us also octahedral with bond angles 90°.
- Central atom is sp3d2 hybridised.
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Answer:
N₂ = 0.7515atm
O₂ = 0.1715atm
NO = 0.0770atm
Explanation:
For the reaction:
N₂(g) + O₂(g) ⇄ 2NO(g)
Where Kp is defined as:
Pressures in equilibrium are:
N₂ = 0.790atm - X
O₂ = 0.210atm - X
NO = 2X
Replacing in Kp:
0.0460 = [2X]² / [0.790atm - X] [0.210atm - X]
0.0460 = 4X² / 0.1659 - X + X²
0.0460X² - 0.0460X + 7.6314x10⁻³ = 4X²
-3.954X² - 0.0460X + 7.6314x10⁻³ = 0
Solving for X:
X = - 0.050 → False answer. There is no negative concentrations.
X = <em>0.0385 atm</em> → Right answer.
Replacing for pressures in equilibrium:
N₂ = 0.790atm - X = <em>0.7515atm</em>
O₂ = 0.210atm - X = <em>0.1715atm</em>
NO = 2X = <em>0.0770atm</em>