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marissa [1.9K]
3 years ago
11

100 ml of gaseous hydrocarbon consumes 300

Chemistry
2 answers:
zhenek [66]3 years ago
6 0

The answer would be a. C2H4(ethylene)

1C2H4+3O2~>2CO2+2H2O

UNO [17]3 years ago
6 0

Answer:

a. C2H4.

Explanation:

Let's look at the balanced equation for C2H4.

C2H4  + 3O2 -->  2CO2 + 2H2O

So 1 mole of this hydrocarbon reacts with 3 moles of oxygen and since  1 mole of one gas occupies the same volume as another gas, the volumes  will be in the ratio 1:3.  So this is the required hydrocarbon.

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True or False? Unbalanced forces cause a change in motion <br> T/F <br><br> How do you know this?
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if a substance causes another substance to be oxidized, that substance is a(n) agent. likewise, the substance that is oxidized i
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If a substance causes another substance to be oxidized, that substance is an oxidizing agent. Likewise, the substance that is oxidized in an electrochemical reaction is always the reducing agent.

An Oxidizing agent is the one that gets reduced by accepting electrons. It causes oxidation because it makes the other substance lose electrons.

Oxidizing agents also transfer one electronegative atom like oxygen to the other chemical substance. Halogens are an example of oxidizing agents.

A reducing agent is the one that gets oxidized because it loses electrons in a redox reaction. It loses electrons and achieve a higher oxidation state. Lithium is an example of a reducing agent.

If you need to learn more about oxidizing and reducing agent, click here

brainly.com/question/20565173?referrer=searchResults

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6 0
2 years ago
How many grams of liquid CF2Cl2 are needed to cool 156 g of water from 42.9 to 20.5 °C? The specific heat of water is 4.184 J/(g
SashulF [63]

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

CF₂Cl₂ is a refrigerant. When it is evaporated, it absorbs heat from water, which cools.

<h3>What is evaporation?</h3>

Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.

  • Step 1: Calculate the heat released by water.

We will use the following expression.

Qw = c × m × ΔT = (4.184 J/g.°C) × 156 g × (20.5 °C - 42.9 °C)

Qw = -14.6 kJ

where,

  • Qw is the heat released by water.
  • c is the specific heat of water.
  • m is the mass of water.
  • ΔT is the change in the temperature of water.

If water releases 14.6 kJ of heat, CF₂Cl₂ absorbs 14.6 kJ of heat (Qr = 14.6 kJ).

  • Step 2: Calculate the mass of the refrigerant required.

We will use the following expression.

Qr = ΔH°evap × m

m = Qr/ΔH°evap = 14.6 kJ / (0.144 kJ/g) = 101 g

where,

  • Qr is the heat absorbed by the refrigerant.
  • ΔH°evap is the heat of vaporization of the refrigerant.
  • m is the mass of the refrigerant.

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

Learn more about evaporation here: brainly.com/question/25310095

4 0
2 years ago
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