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marissa [1.9K]
3 years ago
11

100 ml of gaseous hydrocarbon consumes 300

Chemistry
2 answers:
zhenek [66]3 years ago
6 0

The answer would be a. C2H4(ethylene)

1C2H4+3O2~>2CO2+2H2O

UNO [17]3 years ago
6 0

Answer:

a. C2H4.

Explanation:

Let's look at the balanced equation for C2H4.

C2H4  + 3O2 -->  2CO2 + 2H2O

So 1 mole of this hydrocarbon reacts with 3 moles of oxygen and since  1 mole of one gas occupies the same volume as another gas, the volumes  will be in the ratio 1:3.  So this is the required hydrocarbon.

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A student sets up the following equation...
Sphinxa [80]

Answer:

The answer to your question is given below

Explanation:

From the question given above, the following data were obtained:

Concentration (g/mL) = 0.04 g/mL

Concentration (g/L) =?

We can convert g/mL to g/L by doing the following:

1 g/mL = 1000 g/L

Therefore,

0.04 g/mL = 0.04 g/mL × 1000 g/L / 1 g/mL

0.04 g/mL = 40 g/L

0.04 g/mL is equivalent to 40 g/L.

Thus, the concentration (g/L) is 40 g/L

3 0
3 years ago
A chemist dilutes a 1.0 ml sample of 2.0 m kno3 by adding water to it. if the concentration of the solution that is obtained is
Nitella [24]

A chemist dilutes a 1.0 ml sample of 2.0M KNO₃ by adding water to it. If the concentration of the solution that is obtained is 0.0080 m, then its volume is 250mL.

<h3>How do we calculate volume?</h3>

Volume for the given equation will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ = molarity of KNO₃ = 2M

V₁ = volume of KNO₃ = 1mL

M₂ = molarity of final solution = 0.0080M

V₂ = volume of final solution = ?

On putting these values on the above equation, we get

V₂ = (2)(1) / (0.0080) = 250mL

Hence option (2) is correct.

To know more about molarity, visit the below link:

brainly.com/question/24305514

8 0
2 years ago
Can some help me with this i really don't under stand it you can Have brainliest
PilotLPTM [1.2K]

Answer:

this ez put some over to left and the rest right

Explanation:

8 0
3 years ago
The units of density are kg/m2. If the density of a liquid is 760.0 kg/m' what is the specific volume? a) 1.316 x 10 m2/kg b) 1.
zlopas [31]

Answer:

The correct answer is: 1.316 . 10⁻³ m³/kg.

Explanation:

The density (ρ) of a substance is the ratio of its <em>mass (m)</em> to its <em>volume (V)</em>. At constant temperature and pressure, its value is constant and it is an intrinsic property of materials. The units of density are kg/m³.

\rho = \frac{m}{V}

The specific volume (ν) of a substance is the ratio of its <em>mass</em> to its <em>volume</em>. We can see that it is the reciprocal of density and an intrinsic property of matter as well. Therefore, the units of specific volume are m³/kg.

\nu = \frac{V}{m}=\frac{1}{\rho }

Given we know the density of the liquid, we can use this relationship to find out its specific volume:

\nu =\frac{1}{\rho }=\frac{1}{760.0kg/m^{3} } =1.316 .10^{-3} m^{3} /kg

6 0
3 years ago
N-hexane boils at 68.7 oC at 1.013 bar and the heat of Vaporization is 28850
miss Akunina [59]
He one 28850




C. C c c.
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3 years ago
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