<h3>
Answer:</h3>
56.11 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Compound] KOH
<u>Step 2: Identify</u>
[PT] Molar Mass of K - 39.10 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
<u>Step 3: Find</u>
39.10 + 16.00 + 1.01 = 56.11 g/mol
Answer: 12.92g of CoSO4
Explanation:
Molar Mass of CoSO4 = 59 + 32 + (16x4) = 59 + 32 +64 = 155g/mol
Molarity of CoSO4 = 0.303mol/L
Mass conc. In g/L = Molarity x molar Mass
= 0.303x155 = 46.965g/L
275 grams of water = 0.275L of water
46.965g of CoSO4 dissolves in 1L
Therefore Xg of CoSO4 will dissolve in 0.275L i.e
Xg of CoSO4 = 46.965x0.275 = 12.92g
Therefore 12.92g of CoSO4 is needed
Answer:
20
Explanation:
Hi there!
We need to find the atomic number of an atom that has 20 protons and 20 neutrons
the atomic number of an atom is equivalent to the amount of protons an atom has, as the number of protons determines what element an atom is.
Since the atom has 20 protons, the atomic number of the said atom is <u>20</u>
Hope this helps!
Answer:
Answer is given below:
Explanation:
The way it is made (3) Structure.
The basic unit of life (7) Cell.
Perform the different functions of cell (7) Organelles.
No nucleus and unicellular (1) Prokaryote.
Composed of many cells (6) Tissue.
Concluded that all animals are made of cells (10) Theodore schwann .
Contains the genetic information (2) Nucleus.
Concluded that all plants are made up of cells (9) Matthias Schleilden.
Concluded that all cell came from pre existing cells (10)
Rudolf Virchow.
Has a nucleus and some are unicellular, but mostly
multicellular (4)
Eukaryote
Answer:
0.0400 g for the example given below.
Explanation:
pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.
- By definition,
![pH = -log[H_3O^+]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH_3O%5E%2B%5D)
. - NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation:
. - From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH:
![[NaOH] = [OH^-]](https://tex.z-dn.net/?f=%5BNaOH%5D%20%3D%20%5BOH%5E-%5D)
. - Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain:
![[OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%20%3D%20%5BNaOH%5D%20%3D%20%5Cfrac%7Bn_%7BNaOH%7D%7D%7BV%7D%20%3D%20%5Cfrac%7Bm_%7BNaOH%7D%7D%7BM_%7BNaOH%7DV%7D)
. - We also know that
![pOH = 14.00 - pH = -log[NaOH]](https://tex.z-dn.net/?f=pOH%20%3D%2014.00%20-%20pH%20%3D%20-log%5BNaOH%5D)
. Take the antilog of both sides: ![10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}](https://tex.z-dn.net/?f=10%5E%7B-pOH%7D%20%3D%2010%5E%7BpH%20-%2014.00%7D%20%3D%20%5BNaOH%5D%20%3D%20%5Cfrac%7Bm_%7BNaOH%7D%7D%7BM_%7BNaOH%7DV%7D)
. - Solve for the mass of NaOH:
.
Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:
