Answer:
the answer would be 6.720
Simply subtract the combined mass by the mass of the beaker.
The answer has 3 decimal places because the least amount of decimal places in the equation is 3.
Answer:
Theanswer to your question is:
Limiting reactant = FeCl₃
Excess reactant = 1.66 g of Mg
Explanation:
Data
Mg = 41 g = 24.31 g/mol
FeCl₃ = 175 g = 162.2 g/mol
3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s)
3(24.31) of Mg ------------------ 2(162.2) of FeCl₃
72.93 g of Mg ------------------ 324.4 g of FeCl₃
Theoretical Proportion = 324.4/72.93 = 4.44
Practical proportion = 175 / 41 = 4.2
As the proportion disminishes the limiting reactant is FeCl₃.
Excess reactant
72.93 g of Mg ------------------ 324.4 g of FeCl₃
x ------------------------- 175 g of FeCl₃
x = (175 x 72.93) / 324.4
x = 39.34 g of Mg
Excess = 41 - 39.34
= 1.66 g of Mg
Answer: CuI₂ + Br₂
Explanation:
1) The activity series F > Cl > Br > I means that F is the most active and I is the least active of those four elements (the halogens, group 17 in the periodic table).
The activity is a measure of how eager is an element to react compared to other elements in the series in a single replacement reaction.
2) Choice 1: CuI₂ + Br₂
Since the activity of Br is higher than that of I, Br will react with CuI₂, displacing I, which will be left alone, as per this chemical equation:
CuI₂ + Br₂ → CuBr₂ + I₂
Being I less active than Br, it cannot displace Br in CuBr₂.
3) Choice 2: Cl₂ + AlF₃
Being Cl less active than F, the former will not displace the latter, and the reaction will not proceed.
4) Choice 3: Br₂ + NaCl
Again, being Br less active than Cl, the former will not displace the latter, and the reaction will not proceed.
5) Choice 4: CuF₂ + I₂
Once more, being I less active than F, the former will not displace the latter, and the reaction will not proceed.
Answer:
v = 450 m/s
Explanation:
Given data:
Frequency = 75 Hz
Wavelength = 6 m
Velocity = ?
Solution:
Velocity is the product of frequency and wavelength.
v = f × λ
v = 75 Hz × 6 m
Hz = s⁻¹
v = 75 s⁻¹ × 6 m
v = 450 m/s