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3 years ago

Match the items to use the analogy of time to the vocabulary of chemistry.

Chemistry

2 answers:

antoniya [11.8K]3 years ago

6 0

Answer:

1 year- 1 mole

time in general- amount of matter

1 second- 1 atom/ particle

Svet_ta [14]3 years ago

6 0

Answer:

1 Year => 1 Mole

Time in General => Amount of Matter

1 Second => 1 Atom/Particle

Explanation:

These pairs make the most sense.

Hope it helps!!!

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Directions: Each set of lettered choices below refers to the numbered statements immediately following it. Select the one letter

maksim [4K]

Answer : The only reaction (C) that shows that the same reactant undergoes both oxidation and reduction.

Explanation :

Disproportionation reaction : It is defined as the reaction in which the same reactant undergoes both oxidation and reduction reaction. It is a redox reaction.

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(A) The given balanced reaction is,

$H_2SeO_4(aq)+2Cl^-(aq)+2H^+(aq)\rightarrow H_2SeO_3(aq)+Cl_2(g)+H_2O(l)$

This reaction is a redox reaction but not disproportionation reaction because in this reaction there are two reactants in which chlorine shows oxidation and selenium shows reduction.

(B) The given balanced reaction is,

$S_8(s)+8O_2(g)\rightarrow 8SO_2(g)$

This reaction is a redox reaction but not disproportionation reaction because in this reaction there are two reactants in which sulfur shows oxidation and oxygen shows reduction.

(C) The given balanced reaction is,

$3Br_2(aq)+6OH^-(aq)\rightarrow 5Br^-(aq)+BrO_3^-(aq)+3H_2O(l)$

This reaction is a disproportionation reaction because in this reaction only one reactant bromine that shows both oxidation and reduction reaction.

(D) The given balanced reaction is,

$Ca^{2+}(aq)+SO_4^{2-}(aq)\rightarrow CaSO_4(s)$

This reaction is a combination reaction in which the two reactant react to give a single product. There is no changes in the oxidation state of calcium and sulfate.

(E) The given balanced reaction is,

$PtCl_4(s)+2Cl^-(aq)\rightarrow PtCl_6^{2-}(aq)$

This reaction is a combination reaction in which the two reactant react to give a single product. There is no changes in the oxidation state of platinum and chlorine.

Hence, the only reaction (C) that shows that the same reactant undergoes both oxidation and reduction.

6 0

3 years ago

When a aqueous solution of a certain acid is prepared, the acid is dissociated. Calculate the acid dissociation constant of the

stepan [7]

<h2> $K_a$ = $\dfrac{[H^{+}] [A^{-}]}{[HA]}$ </h2>

Explanation:

When an aqueous solution of a certain acid is prepared it is dissociated is as follows-

${\displaystyle {\ce {HA$ ⇄ ${H^+}+{A^{-}}} }}$

Here HA is a protonic acid such as acetic acid, $CH_3COOH$

The double arrow signifies that it is an equilibrium process, which means the dissociation and recombination of the acid occur simultaneously.

The acid dissociation constant can be given by -

$K_a$ = $\dfrac{[H^{+}] [A^{-}]}{[HA]}$

The reaction is can also be represented by Bronsted and lowry -

$\\{\displaystyle {\ce {{HA}+ H_2O}$ ⇄ $[H_3O^+] [A^-]$

Then the dissociation constant will be

$K_a$ = $\dfrac{[H_3O^{+}] [A^{-}]}{[HA]}$

Here, $K_a$ is the dissociation constant of an acid.

6 0

4 years ago

What's the formula of mercury (I) dioxonitrate III

steposvetlana [31]

<h2>Answer:</h2>

<h2>Explanation:</h2>

<h3>Formula of mercury ( 1 ) dioxonitrate 111 is Hg2 ( NO2 )2//</h3>

7 0

3 years ago

The speed of light is around 6.706×10^8 miles per hour. What is the speed of light in units of miles per minute?

Sindrei [870]

<u>Answer:</u> The speed of light in miles per minutes is $1.117\times 10^7miles/min$

<u>Explanation:</u>

We are given the speed of light is $6.706\times 10^8miles/hr$ and we need to convert it into miles/min. So, we use the converion factor:

1 hour = 60 minutes

Converting that quantity into miles/minutes, we get:

$(\frac{6.706miles}{1hr})(\frac{1hr}{60min})=\frac{1.117\times 10^7miles}{min}$

Hence, the speed of light in miles per minutes is $1.117\times 10^7miles/min$

7 0

3 years ago

Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i

ankoles [38]

First, we need to get the value of Ka:

when Ka = Kw / Kb

we have Kb = 1.8 x 10^-5

and Kw = 3.99 x 10^-16 so, by substitution:

Ka = (3.99 x 10^-16) / (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

NH4+ + H2O →NH3 + H+
intial 0.013 0 0

change -X +X +X

Equ (0.013-X) X X

when Ka = [NH3][H+] / [NH4+]

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X) by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]

= -㏒(5.35 x 10^-7)
= 6.27

6 0

3 years ago