Question

How many moles of HCl are present in 0.70 L of a 0.33 M HCl solution? (molar mass of HCl = 36.46 g/mol)

Answer 1

Answer:-

0.231 moles

Explanation:-

From the question we are told that

Volume of HCl solution = 0.70 L

Strength of HCl solution = 0.33 M

Here M stands for molarity. Molarity is the number of moles of the substance present per Litre of solution. So in place of M we can write moles / L

Number of moles of HCl solution = Volume of HCl solution x Strength of HCl solution

= 0.70 L x 0.33 moles / L

= 0.231 moles.

0.231 moles of HCl are present in 0.70 L of a 0.33 M HCl solution